Convert to polar coordinates.
$\left(\sqrt2,\frac{\pi}{2}\right)$
$\left(2,\frac{\pi}{2}\right)$
Convert to polar form.
$\left(3\sqrt2,\frac{5\pi}{4}\right)$
$\left(3\sqrt2,\frac{\pi}{4}\right)$
$\left(3,\frac{\pi}{4}\right)$
$\left(3,\frac{5\pi}{4}\right)$
$\left(-3,-\frac{\pi}{4}\right)$