Sets

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Theory of Positive Integers › Sets

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1

Let

$S:\begin{Bmatrix} -10,-8,-6,-4,-2,0,2,4 \end{Bmatrix}$

if is some condition of such that it can be described as $\begin{Bmatrix} x\ \epsilon\ S: p(x) \end{Bmatrix}$ what is when $B=\begin{Bmatrix} 2,4 \end{Bmatrix}$ ?

$B=\begin{Bmatrix} x\ \epsilon\ S: x>0 \end{Bmatrix}$

CORRECT

$B=\begin{Bmatrix} x\ \epsilon\ S: x\geq0 \end{Bmatrix}$

0

$B=\begin{Bmatrix} x\ \epsilon\ S: x<0 \end{Bmatrix}$

0

$B=\begin{Bmatrix} x\ \epsilon\ S: x\leq0 \end{Bmatrix}$

0

None of the answers

0

Explanation

First, identify what is given.

$S:\begin{Bmatrix} -10,-8,-6,-4,-2,0,2,4 \end{Bmatrix}$

$B=\begin{Bmatrix} 2,4 \end{Bmatrix}$

and can be described in the following format

$B=\begin{Bmatrix} x\ \epsilon\ S: p(x) \end{Bmatrix}$

Since contains the elements in that are greater than zero, can be written as follows.

$B=\begin{Bmatrix} x\ \epsilon\ S: x>0 \end{Bmatrix}$

2

Let

$S:\begin{Bmatrix} -6,-4,-2,0,2,4 \end{Bmatrix}$

if is some condition of such that it can be described as $\begin{Bmatrix} x\ \epsilon\ S: p(x) \end{Bmatrix}$ what is when $B=\begin{Bmatrix} -6,-4,-2,0 \end{Bmatrix}$ ?

$B=\begin{Bmatrix} x\ \epsilon\ S: x\leq0 \end{Bmatrix}$

CORRECT

$B=\begin{Bmatrix} x\ \epsilon\ S: x<0 \end{Bmatrix}$

0

$B=\begin{Bmatrix} x\ \epsilon\ S: x\geq0 \end{Bmatrix}$

0

$B=\begin{Bmatrix} x\ \epsilon\ S: x>0 \end{Bmatrix}$

0

None of the answers

0

Explanation

First, identify what is given.

$S:\begin{Bmatrix} -6,-4,-2,0,2,4 \end{Bmatrix}$

$B=\begin{Bmatrix} -6,-4,-2,0 \end{Bmatrix}$

and can be described in the following format

$B=\begin{Bmatrix} x\ \epsilon\ S: p(x) \end{Bmatrix}$

Since contains the elements in that are less than or zero, can be written as follows.

$B=\begin{Bmatrix} x\ \epsilon\ S: x\leq0 \end{Bmatrix}$

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