Summarizing Numeric Data with Measures of Center and Spread(TEKS.Math.6.12.C)

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Texas 6th Grade Math › Summarizing Numeric Data with Measures of Center and Spread(TEKS.Math.6.12.C)

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1

A data set has these five-number summary values: min=12, Q1=18, median=24, Q3=31, max=40. What is the IQR (Q3 − Q1)?

13

CORRECT

11

0

19

0

28

0

Explanation

Compute the interquartile range: $IQR = Q_3 - Q_1 = 31 - 18 = 13$. The IQR of 13 shows the spread of the middle half of the data.

2

Ordered data (least to greatest): 3, 5, 5, 6, 7, 8, 9, 10, 12, 12, 14, 20. Which statement best compares the range and IQR for this set?

The range and IQR are equal.

0

The range is greater than the IQR.

CORRECT

The IQR is greater than the range.

0

The IQR is 17 and the range is 6.5.

0

Explanation

Range: $20 - 3 = 17$. For quartiles (12 values): $Q_1$ is the median of 3,5,5,6,7,8 → average of 5 and 6 is 5.5. $Q_3$ is the median of 9,10,12,12,14,20 → average of 12 and 12 is 12. So $IQR = Q_3 - Q_1 = 12 - 5.5 = 6.5$. Since 17 > 6.5, the range is greater than the IQR. This suggests the full spread is wider than the middle spread, possibly due to an outlier.

3

Ordered data (least to greatest): 12, 13, 15, 17, 18, 21, 22, 24, 30. What is the IQR (Q3 − Q1)?

9

CORRECT

7

0

8

0

12

0

Explanation

There are 9 values. The median is the 5th value (18). Lower half: 12, 13, 15, 17 → $Q_1$ is the average of 13 and 15, which is 14. Upper half: 21, 22, 24, 30 → $Q_3$ is the average of 22 and 24, which is 23. So $IQR = Q_3 - Q_1 = 23 - 14 = 9$. The middle half of the data varies by 9.