Data Analysis and Probability - SSAT Middle Level Quantitative
Card 1 of 996
Five candidates ran for mayor of Madison City; the above circle graph shows the share of the vote that each won. Which of the following would be the most reasonable estimate of the percent of the vote Lyle won?
Five candidates ran for mayor of Madison City; the above circle graph shows the share of the vote that each won. Which of the following would be the most reasonable estimate of the percent of the vote Lyle won?
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The sector representing Lyle is roughly one-tenth to one-eighth of the circle - in other words, 10-12 % of it. This is the approximate percent of the vote won by Lyle.
The sector representing Lyle is roughly one-tenth to one-eighth of the circle - in other words, 10-12 % of it. This is the approximate percent of the vote won by Lyle.
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Dave has a sock drawer with 8 blue and 10 black socks.
If Dave pulls out one black sock, what is the probability that the next sock he pulls out of the drawer is also black?
Dave has a sock drawer with 8 blue and 10 black socks.
If Dave pulls out one black sock, what is the probability that the next sock he pulls out of the drawer is also black?
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Since the first sock that Dave pulls out is black, there are 17 remaining socks in the drawer, 8 blue and 9 black. The probability that Dave will choose another black is sock is therefore 9 out of 17.
Since the first sock that Dave pulls out is black, there are 17 remaining socks in the drawer, 8 blue and 9 black. The probability that Dave will choose another black is sock is therefore 9 out of 17.
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All of the clubs are removed from a standard fifty-two-card deck. Two cards are then dealt without replacement. What is the probability that both cards will be red?
All of the clubs are removed from a standard fifty-two-card deck. Two cards are then dealt without replacement. What is the probability that both cards will be red?
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Wihtout the clubs, the deck comprises 39 cards, 26 of which are red.
The probability that the first card will be red will be 
. The probability that the second will then also be red will be 
. Multiply the probabilities, and result is 
Wihtout the clubs, the deck comprises 39 cards, 26 of which are red.
The probability that the first card will be red will be
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A pair of fair dice are rolled. What is the probability that the sum will be a multiple of 4?
A pair of fair dice are rolled. What is the probability that the sum will be a multiple of 4?
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There are three possible multiples of 4 that can come out: 4, 8, and 12. There are 36 equally probable outcomes; the following will result in a multiple of 4:
These are 9 outcomes out of 36, making the probability 
There are three possible multiples of 4 that can come out: 4, 8, and 12. There are 36 equally probable outcomes; the following will result in a multiple of 4:
These are 9 outcomes out of 36, making the probability
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A pair of fair dice are rolled. What is the probability that the sum will be a multiple of 3?
A pair of fair dice are rolled. What is the probability that the sum will be a multiple of 3?
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There are four possible multiples of 3 that can come out: 3,6,9, and 12. There are 36 equally probable outcomes; the following will result in a multiple of 3:
These are 12 outcomes out of 36, making the probability 
There are four possible multiples of 3 that can come out: 3,6,9, and 12. There are 36 equally probable outcomes; the following will result in a multiple of 3:
These are 12 outcomes out of 36, making the probability
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Some balls are placed in a hat - ten red, four blue, six yellow. What is the probability that a randomly drawn ball will not be blue?
Some balls are placed in a hat - ten red, four blue, six yellow. What is the probability that a randomly drawn ball will not be blue?
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There are 20 balls in the hat. All but four - that is, sixteen - are blue, so the probability of a draw resulting in a non-blue ball is 
There are 20 balls in the hat. All but four - that is, sixteen - are blue, so the probability of a draw resulting in a non-blue ball is
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The red jacks are removed from a standard deck of fifty-two cards. What is the probability that a card randomly drawn from that modified deck will be black?
The red jacks are removed from a standard deck of fifty-two cards. What is the probability that a card randomly drawn from that modified deck will be black?
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The removal of two red jacks - and no black cards - results in there being fifty cards, twenty-six of them black. Therefore, the probability of a randomly drawn card being black is 
.
The removal of two red jacks - and no black cards - results in there being fifty cards, twenty-six of them black. Therefore, the probability of a randomly drawn card being black is
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A standard deck of cards is modified by adding the red threes from another deck. What is the probability that a card randomly drawn from that modified deck will be a red card?
A standard deck of cards is modified by adding the red threes from another deck. What is the probability that a card randomly drawn from that modified deck will be a red card?
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The addition of two red threes from another deck results in the deck comprising fifty-four cards, twenty-eight of which are red. Therefore, the probability of a randomly drawn card being red is
The addition of two red threes from another deck results in the deck comprising fifty-four cards, twenty-eight of which are red. Therefore, the probability of a randomly drawn card being red is
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A standard deck of cards is modified by adding the red queens from another deck. What is the probability that a card randomly drawn from that modified deck will be a face card (jack, queen, king)?
A standard deck of cards is modified by adding the red queens from another deck. What is the probability that a card randomly drawn from that modified deck will be a face card (jack, queen, king)?
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There are four cards of each rank in a standard deck; since three ranks - jacks, queens, kings - are considered face cards, this makes twelve face cards out of the fifty-two. But two more face cards - two red queens - have been introduced, so now there are fourteen face cards out of fifty-four. This makes the probability of a randomly drawn card being a face card
There are four cards of each rank in a standard deck; since three ranks - jacks, queens, kings - are considered face cards, this makes twelve face cards out of the fifty-two. But two more face cards - two red queens - have been introduced, so now there are fourteen face cards out of fifty-four. This makes the probability of a randomly drawn card being a face card
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In a bag of marbles, there are 
blue marbles, 
red marbles, and 
green marbles. What is the probability of drawing two blue marbles in a row?
In a bag of marbles, there are
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The probability of drawing a blue marble on the first try is 
, since there are 
blue marbles out of a total of 
marbles. The probability of drawing a second blue marble is 
, since now there are 
blue marbles remaining out of a total of 
remaining marbles. The probability of drawing two blue marbles in a row is the product of the individual probabilities: 
.
The probability of drawing a blue marble on the first try is
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If Mark flips a coin and then rolls a die, what are the odds that the coin will be heads and that the die will land on a multiple of 3?
If Mark flips a coin and then rolls a die, what are the odds that the coin will be heads and that the die will land on a multiple of 3?
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If Mark flips a coin, the chance that it will land on heads is 
. On a die, there are 2 out of 6 numbers that are a multiple of 3 (3 and 6); therefore, there is a 
chance that the dice will be a multiple of 3.
The probability that the coin will land on heads and that the dice will be a multiple of 3 is:
If Mark flips a coin, the chance that it will land on heads is
The probability that the coin will land on heads and that the dice will be a multiple of 3 is:
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Lisa and Fred were flipping a quarter and recording whether it was heads or tails. What is the probability they flip a quarter and it lands on heads, heads, tails, heads, tails? (H,H,T,H,T)
Lisa and Fred were flipping a quarter and recording whether it was heads or tails. What is the probability they flip a quarter and it lands on heads, heads, tails, heads, tails? (H,H,T,H,T)
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There are two possibilities every time you flip a coin and only one outcome. Therefore the probability for flipping either heads or tails each time is 
. When you have multiple trials in a row you multiply the probabilities of each outcome by each other.
There are two possibilities every time you flip a coin and only one outcome. Therefore the probability for flipping either heads or tails each time is
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A large box contains some balls, each of which is marked with a number; one ball is marked with a "1", two balls are marked with a "2". and so forth up to ten balls with a "10". A blank ball is also included.
Give the probability that a ball drawn at random will NOT be an odd-numbered ball.
A large box contains some balls, each of which is marked with a number; one ball is marked with a "1", two balls are marked with a "2". and so forth up to ten balls with a "10". A blank ball is also included.
Give the probability that a ball drawn at random will NOT be an odd-numbered ball.
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The number of balls in the box is
;
The number of odd-numbered balls is
.
Therefore, there are 
balls that are not marked with an odd number, making the probability that one of these will be drawn 
.
The number of balls in the box is
The number of odd-numbered balls is
Therefore, there are
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A large box contains some balls, each marked with a whole number from "1" to "10". Each odd number is represented by one ball, which is red; each even number is represented by two balls, one red and one green. Five blank yellow balls are then put in the box.
Give the probability that a randomly-drawn ball will be green.
A large box contains some balls, each marked with a whole number from "1" to "10". Each odd number is represented by one ball, which is red; each even number is represented by two balls, one red and one green. Five blank yellow balls are then put in the box.
Give the probability that a randomly-drawn ball will be green.
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Each whole number from one to ten will be represented by a red ball, for a total of ten balls; each even number will be represented by a green ball, for a total of five balls; there will also be five unmarked yellow balls. The number of balls in the box will be 
, 5 of which are green, making the probability of a random draw resulting in a green ball
.
Each whole number from one to ten will be represented by a red ball, for a total of ten balls; each even number will be represented by a green ball, for a total of five balls; there will also be five unmarked yellow balls. The number of balls in the box will be
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A large box contains some balls, each of which is marked with a number; one ball is marked with a "1", two balls are marked with a "2". and so forth up to ten balls with a "10". Two blank balls are also included.
Give the probability that a ball drawn at random will be an even-numbered ball.
A large box contains some balls, each of which is marked with a number; one ball is marked with a "1", two balls are marked with a "2". and so forth up to ten balls with a "10". Two blank balls are also included.
Give the probability that a ball drawn at random will be an even-numbered ball.
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The number of balls in the box is
.
The number of balls with even numbers is
.
Therefore, if a ball is drawn at random, the probability that an even-numbered ball will be selected is
The number of balls in the box is
The number of balls with even numbers is
Therefore, if a ball is drawn at random, the probability that an even-numbered ball will be selected is
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A large box contains some balls, each of which is marked with a letter of the alphabet. Each vowel is represented by three balls, one red and two blue; each consonant is represented by one ball, which is red. Give the probability that a randomly drawn ball will be blue.
Note: For purposes of this question, "Y" is considered a consonant.
A large box contains some balls, each of which is marked with a letter of the alphabet. Each vowel is represented by three balls, one red and two blue; each consonant is represented by one ball, which is red. Give the probability that a randomly drawn ball will be blue.
Note: For purposes of this question, "Y" is considered a consonant.
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Each of the 26 letters is represented by one red ball; in addition, each of the five vowels is represented by two blue balls for a total of 
blue balls. The total number of balls is
.
The probability that a random draw will result in a blue ball being selected is
.
Each of the 26 letters is represented by one red ball; in addition, each of the five vowels is represented by two blue balls for a total of
The probability that a random draw will result in a blue ball being selected is
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Find the probability of drawing a 5 from a deck of cards.
Find the probability of drawing a 5 from a deck of cards.
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To find the probability of an event, we will use the following formula:
Now, we will calculate the following:
because there are 4 different ways we can draw a 5 from a deck of cards:
- 5 of hearts
- 5 of diamonds
- 5 of spades
- 5 of clubs
Now, we will calculate the following:
because there are 52 different cards we could potentially draw from a deck.
So, we will substitute. We get
Therefore, the probability of drawing a 5 from a deck of cards is 
.
To find the probability of an event, we will use the following formula:
Now, we will calculate the following:
because there are 4 different ways we can draw a 5 from a deck of cards:
- 5 of hearts
- 5 of diamonds
- 5 of spades
- 5 of clubs
Now, we will calculate the following:
because there are 52 different cards we could potentially draw from a deck.
So, we will substitute. We get
Therefore, the probability of drawing a 5 from a deck of cards is
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A classroom contains the following:
- 14 girls
- 17 boys
Find the probability the teacher calls on a boy.
A classroom contains the following:
- 14 girls
- 17 boys
Find the probability the teacher calls on a boy.
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To find the probability of an event, we will use the following formula:
Now, given the event of calling on a boy, we can calculate:
because there are 17 boys in the classroom who can be called on.
We can also calculate the following:
because there are 31 total students (14 girls + 17 boys = 31 students) who could potentially be called on.
Now, we can substitute. We get
Therefore, the probability of the teacher calling on a boy is 
.
To find the probability of an event, we will use the following formula:
Now, given the event of calling on a boy, we can calculate:
because there are 17 boys in the classroom who can be called on.
We can also calculate the following:
because there are 31 total students (14 girls + 17 boys = 31 students) who could potentially be called on.
Now, we can substitute. We get
Therefore, the probability of the teacher calling on a boy is
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In a group of 4 books, the average number of pages is is 10. Juan adds a book with 20 pages to the group. What is the new average number of pages?
In a group of 4 books, the average number of pages is is 10. Juan adds a book with 20 pages to the group. What is the new average number of pages?
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If the average of 4 books was 10, then the total number of pages was 
. Adding in the 20 new pages, but now dividing by 5 you get 
.
If the average of 4 books was 10, then the total number of pages was
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On the first four exams, Charley scored 92, 88, 76, and 74. Charley wants to have a test average of 85%. What must Charley score on the fifth exam to average 85%?
On the first four exams, Charley scored 92, 88, 76, and 74. Charley wants to have a test average of 85%. What must Charley score on the fifth exam to average 85%?
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The summation of the first four exams equals 330. Using the equation for average, Charley needs to get a 95 on the last exam.
The summation of the first four exams equals 330. Using the equation for average, Charley needs to get a 95 on the last exam.
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