How to find the solution to a rational equation with LCD

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PSAT Math › How to find the solution to a rational equation with LCD

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1

Linesmb1

bm/(_m_2 + 1)

0

–bm/(_m_2 + 1)

0

–b/(m + 1)

0

–b/(_m_2 – 1)

0

b/(_m_2 + 1)

CORRECT

Explanation

Linesmb5

Linesmb4

2

In the equation below, , , and are non-zero numbers. What is the value of in terms of and ?

$\frac{1}{m^3}-\frac{1}{k^2}=\frac{1}{p}$

$m=(\frac{p+k^2}{2})^3$

0

$m=\frac{p^2k^3}{p+k^2}$

0

$m=p^{\frac{1}{2}}-k^{\frac{1}{3}}$

0

$m=(\frac{p+k^2}{pk^2})^{\frac{1}{3}}$

0

$m=(\frac{pk^2}{p+k^2})^{\frac{1}{3}}$

CORRECT

Explanation

Pkm_7-21-13

Pkm2_7-21-13

3

Rational_5

–2

0

–1

0

0

0

1

0

2

CORRECT

Explanation

Rational_2

Rational_3

Rational_4

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