How to multiply fractions - PSAT Math
Card 1 of 56
Sally bought five computers for her office that cost $300, $405, $485, $520, and $555 respectively. She made a down payment of 2/5 the total cost and paid the rest in nine equal payments over the next nine months. Assuming no tax and no interest, what is the value of each of the nine payments?
Sally bought five computers for her office that cost $300, $405, $485, $520, and $555 respectively. She made a down payment of 2/5 the total cost and paid the rest in nine equal payments over the next nine months. Assuming no tax and no interest, what is the value of each of the nine payments?
Tap to reveal answer
The total cost of the 5 computers is 2265.
2/5 of 2265 = 906, which is what Sally pays up front.
2265 – 906 = 1359, which is what Sally still owes.
1359/9 = 151, which is the value of each of the 9 equal payments.
The total cost of the 5 computers is 2265.
2/5 of 2265 = 906, which is what Sally pays up front.
2265 – 906 = 1359, which is what Sally still owes.
1359/9 = 151, which is the value of each of the 9 equal payments.
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The price of a computer is reduced by 1/8. The new price is then reduced by 1/6. What fraction of the original price is the current price?
The price of a computer is reduced by 1/8. The new price is then reduced by 1/6. What fraction of the original price is the current price?
Tap to reveal answer
Let the original price = p.
After the first reduction, the price is (7/8)p
After the second reduction, the price is (5/6)(7/8)p = (35/48)p
Let the original price = p.
After the first reduction, the price is (7/8)p
After the second reduction, the price is (5/6)(7/8)p = (35/48)p
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If a car travels at 30 mph, how many feet per second does travel?
If a car travels at 30 mph, how many feet per second does travel?
Tap to reveal answer
30 miles / 1 hour * 5280 ft / 1 mile * 3600 seconds / 1 hour = 44 ft/sec
30 miles / 1 hour * 5280 ft / 1 mile * 3600 seconds / 1 hour = 44 ft/sec
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In a group of 20 children, 25% are girls. How many boys are there?
In a group of 20 children, 25% are girls. How many boys are there?
Tap to reveal answer
Since 
of the children are girls, this totals to 
girls in the group.
boys.
Since
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If xy = 1 and 0 < x < 1, then which of the following must be true?
If xy = 1 and 0 < x < 1, then which of the following must be true?
Tap to reveal answer
If x is between 0 and 1, it must be a proper fraction (e.g., ½ or ¼). Solving the first equation for y, y = 1/x. When you divide 1 by a proper fraction between 0 and 1, the result is the reciprocal of that fraction, which will always be greater than 1.
To test this out, pick any fraction. Say x = ½. This makes y = 2.
If x is between 0 and 1, it must be a proper fraction (e.g., ½ or ¼). Solving the first equation for y, y = 1/x. When you divide 1 by a proper fraction between 0 and 1, the result is the reciprocal of that fraction, which will always be greater than 1.
To test this out, pick any fraction. Say x = ½. This makes y = 2.
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Before going to school, Joey ran 1/3 of his daily total miles. In gym class, Joey did 2/3 of the remainder. What part of his daily total miles was left for after school?
Before going to school, Joey ran 1/3 of his daily total miles. In gym class, Joey did 2/3 of the remainder. What part of his daily total miles was left for after school?
Tap to reveal answer
Before school, Joey did 1/3 of the total miles. In school, Joey did 2/3 of the remaining 2/3, or 4/9 of the running. When added to his in school run, his before school run of 3/9 brings his completed miles to 7/9 of his dialy total. Thus, only 2/9 of the total miles are left for after school.
Before school, Joey did 1/3 of the total miles. In school, Joey did 2/3 of the remaining 2/3, or 4/9 of the running. When added to his in school run, his before school run of 3/9 brings his completed miles to 7/9 of his dialy total. Thus, only 2/9 of the total miles are left for after school.
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Tap to reveal answer
Remember, when you multiply fractions, you can directly multiply their denominators and their numerators; therefore, you can begin this problem by making it into one large fraction:
Now, you could multiply all of this out and then divide. However, you can cancel things immediately. The 
goes into the 
and the 
into the 
. Thus, you have:
Remember, when you multiply fractions, you can directly multiply their denominators and their numerators; therefore, you can begin this problem by making it into one large fraction:
Now, you could multiply all of this out and then divide. However, you can cancel things immediately. The
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Simplify:
Simplify:
Tap to reveal answer
First, begin by remembering that 
is the same as 
:
Next, recall that you multiply fractions by multiplying the numerators and denominators by each other. It is very simple. This would give you:
Now, you can cancel the 
and the 
:
Next, you can reduce the 
and the 
:
You can also reduce the resulting 
and the 
:
First, begin by remembering that
Next, recall that you multiply fractions by multiplying the numerators and denominators by each other. It is very simple. This would give you:
Now, you can cancel the
Next, you can reduce the
You can also reduce the resulting
← Didn't Know|Knew It →
If a car travels at 30 mph, how many feet per second does travel?
If a car travels at 30 mph, how many feet per second does travel?
Tap to reveal answer
30 miles / 1 hour * 5280 ft / 1 mile * 3600 seconds / 1 hour = 44 ft/sec
30 miles / 1 hour * 5280 ft / 1 mile * 3600 seconds / 1 hour = 44 ft/sec
← Didn't Know|Knew It →
Before going to school, Joey ran 1/3 of his daily total miles. In gym class, Joey did 2/3 of the remainder. What part of his daily total miles was left for after school?
Before going to school, Joey ran 1/3 of his daily total miles. In gym class, Joey did 2/3 of the remainder. What part of his daily total miles was left for after school?
Tap to reveal answer
Before school, Joey did 1/3 of the total miles. In school, Joey did 2/3 of the remaining 2/3, or 4/9 of the running. When added to his in school run, his before school run of 3/9 brings his completed miles to 7/9 of his dialy total. Thus, only 2/9 of the total miles are left for after school.
Before school, Joey did 1/3 of the total miles. In school, Joey did 2/3 of the remaining 2/3, or 4/9 of the running. When added to his in school run, his before school run of 3/9 brings his completed miles to 7/9 of his dialy total. Thus, only 2/9 of the total miles are left for after school.
← Didn't Know|Knew It →
Sally bought five computers for her office that cost $300, $405, $485, $520, and $555 respectively. She made a down payment of 2/5 the total cost and paid the rest in nine equal payments over the next nine months. Assuming no tax and no interest, what is the value of each of the nine payments?
Sally bought five computers for her office that cost $300, $405, $485, $520, and $555 respectively. She made a down payment of 2/5 the total cost and paid the rest in nine equal payments over the next nine months. Assuming no tax and no interest, what is the value of each of the nine payments?
Tap to reveal answer
The total cost of the 5 computers is 2265.
2/5 of 2265 = 906, which is what Sally pays up front.
2265 – 906 = 1359, which is what Sally still owes.
1359/9 = 151, which is the value of each of the 9 equal payments.
The total cost of the 5 computers is 2265.
2/5 of 2265 = 906, which is what Sally pays up front.
2265 – 906 = 1359, which is what Sally still owes.
1359/9 = 151, which is the value of each of the 9 equal payments.
← Didn't Know|Knew It →
The price of a computer is reduced by 1/8. The new price is then reduced by 1/6. What fraction of the original price is the current price?
The price of a computer is reduced by 1/8. The new price is then reduced by 1/6. What fraction of the original price is the current price?
Tap to reveal answer
Let the original price = p.
After the first reduction, the price is (7/8)p
After the second reduction, the price is (5/6)(7/8)p = (35/48)p
Let the original price = p.
After the first reduction, the price is (7/8)p
After the second reduction, the price is (5/6)(7/8)p = (35/48)p
← Didn't Know|Knew It →
If xy = 1 and 0 < x < 1, then which of the following must be true?
If xy = 1 and 0 < x < 1, then which of the following must be true?
Tap to reveal answer
If x is between 0 and 1, it must be a proper fraction (e.g., ½ or ¼). Solving the first equation for y, y = 1/x. When you divide 1 by a proper fraction between 0 and 1, the result is the reciprocal of that fraction, which will always be greater than 1.
To test this out, pick any fraction. Say x = ½. This makes y = 2.
If x is between 0 and 1, it must be a proper fraction (e.g., ½ or ¼). Solving the first equation for y, y = 1/x. When you divide 1 by a proper fraction between 0 and 1, the result is the reciprocal of that fraction, which will always be greater than 1.
To test this out, pick any fraction. Say x = ½. This makes y = 2.
← Didn't Know|Knew It →
In a group of 20 children, 25% are girls. How many boys are there?
In a group of 20 children, 25% are girls. How many boys are there?
Tap to reveal answer
Since of the children are girls, this totals to girls in the group.
boys.
Since
← Didn't Know|Knew It →
Tap to reveal answer
Remember, when you multiply fractions, you can directly multiply their denominators and their numerators; therefore, you can begin this problem by making it into one large fraction:
Now, you could multiply all of this out and then divide. However, you can cancel things immediately. The goes into the and the into the . Thus, you have:
Remember, when you multiply fractions, you can directly multiply their denominators and their numerators; therefore, you can begin this problem by making it into one large fraction:
Now, you could multiply all of this out and then divide. However, you can cancel things immediately. The
← Didn't Know|Knew It →
Simplify:
Simplify:
Tap to reveal answer
First, begin by remembering that is the same as :
Next, recall that you multiply fractions by multiplying the numerators and denominators by each other. It is very simple. This would give you:
Now, you can cancel the and the :
Next, you can reduce the and the :
You can also reduce the resulting and the :
First, begin by remembering that
Next, recall that you multiply fractions by multiplying the numerators and denominators by each other. It is very simple. This would give you:
Now, you can cancel the
Next, you can reduce the
You can also reduce the resulting
← Didn't Know|Knew It →
In a group of 20 children, 25% are girls. How many boys are there?
In a group of 20 children, 25% are girls. How many boys are there?
Tap to reveal answer
Since of the children are girls, this totals to girls in the group.
boys.
Since
← Didn't Know|Knew It →
If xy = 1 and 0 < x < 1, then which of the following must be true?
If xy = 1 and 0 < x < 1, then which of the following must be true?
Tap to reveal answer
If x is between 0 and 1, it must be a proper fraction (e.g., ½ or ¼). Solving the first equation for y, y = 1/x. When you divide 1 by a proper fraction between 0 and 1, the result is the reciprocal of that fraction, which will always be greater than 1.
To test this out, pick any fraction. Say x = ½. This makes y = 2.
If x is between 0 and 1, it must be a proper fraction (e.g., ½ or ¼). Solving the first equation for y, y = 1/x. When you divide 1 by a proper fraction between 0 and 1, the result is the reciprocal of that fraction, which will always be greater than 1.
To test this out, pick any fraction. Say x = ½. This makes y = 2.
← Didn't Know|Knew It →
Before going to school, Joey ran 1/3 of his daily total miles. In gym class, Joey did 2/3 of the remainder. What part of his daily total miles was left for after school?
Before going to school, Joey ran 1/3 of his daily total miles. In gym class, Joey did 2/3 of the remainder. What part of his daily total miles was left for after school?
Tap to reveal answer
Before school, Joey did 1/3 of the total miles. In school, Joey did 2/3 of the remaining 2/3, or 4/9 of the running. When added to his in school run, his before school run of 3/9 brings his completed miles to 7/9 of his dialy total. Thus, only 2/9 of the total miles are left for after school.
Before school, Joey did 1/3 of the total miles. In school, Joey did 2/3 of the remaining 2/3, or 4/9 of the running. When added to his in school run, his before school run of 3/9 brings his completed miles to 7/9 of his dialy total. Thus, only 2/9 of the total miles are left for after school.
← Didn't Know|Knew It →
Sally bought five computers for her office that cost $300, $405, $485, $520, and $555 respectively. She made a down payment of 2/5 the total cost and paid the rest in nine equal payments over the next nine months. Assuming no tax and no interest, what is the value of each of the nine payments?
Sally bought five computers for her office that cost $300, $405, $485, $520, and $555 respectively. She made a down payment of 2/5 the total cost and paid the rest in nine equal payments over the next nine months. Assuming no tax and no interest, what is the value of each of the nine payments?
Tap to reveal answer
The total cost of the 5 computers is 2265.
2/5 of 2265 = 906, which is what Sally pays up front.
2265 – 906 = 1359, which is what Sally still owes.
1359/9 = 151, which is the value of each of the 9 equal payments.
The total cost of the 5 computers is 2265.
2/5 of 2265 = 906, which is what Sally pays up front.
2265 – 906 = 1359, which is what Sally still owes.
1359/9 = 151, which is the value of each of the 9 equal payments.
← Didn't Know|Knew It →