Faraday's Law of Induction

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Physics › Faraday's Law of Induction

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A single string of wire has a resistance of $10\Omega$ . If the wire is connected to a power source, what is the strength of the magnetic field away from the wire?

$\mu_o=4\pi \times 10^{-7}\frac{T\cdot m}{A}$

$2.4\times 10^{-5}T$

CORRECT

$7.6\times 10^{-5}T$

$2.4\times 10^{-7}T$

$2.0\times 10^{-6}T$

Explanation

So this is all about the magnetic field strength around a current carrying wire.

The equation for this is:

$B = \frac{\mu _{0}I}{2\Pi r}$

But you must use Ohm's Law in order to find the current in the wire.

Since the wire has $10\Omega$ of resistance and the voltage through the wire is , that means the current in the wire is .

Being sure to change into , plug everything in and get the answer, which is

$2.4\times 10^{-5}T$

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