Using Identities of Squared Functions

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Factor and simplify $\frac{\sin^2x-9}{\sin x-3}$ .

$\sin x+3$

CORRECT

$\cos^2 x+3$

0

$\sin x \cos x$

0

$\csc x$

0

This is already it's most reduced form.

0

Explanation

To reduce $\frac{\sin^2x-9}{\sin x-3}$ , factor the numerator: $\frac{(\sin x-3)(\sin x+3)}{\sin x-3}$

Notice that we can cancel out a $\sin x -3$ .

This leaves us with $\sin x +3$ .

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