Mean - ISEE Middle Level Quantitative Reasoning

Card 0 of 825

Question

Give the mean of the data set (nearest tenth, if applicable):

$\left \{ 56,78,98,85,77,73 \right \}$

Answer

Add the six elements and divide the sum by 6:

$467 \div 6 \approx 77.8$

Compare your answer with the correct one above

Question

Give the mean of the data set $\left \{ 2, 4, 8, 16, 32, 64\right \}$

Answer

There are six elements, so to find the mean, add the elements and divide by six:

$\left ( 2+4+8+16+32+64 \right )\div 6 = 126 \div 6 = 21$

Compare your answer with the correct one above

Question

Give the mean of the following nine scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68, 70 \right \}$

Answer

Divide the sum of the scores by nine:

$\frac{ 61 + 67+ 80+ 72+ 76+73+90+68+70}{9} = \frac{ 657}{9} = 73$

Compare your answer with the correct one above

Question

Give the mean of the data set $\left \{ 2, 4, 8, 16, 32, 64\right \}$

Answer

There are six elements, so to find the mean, add the elements and divide by six:

$\left ( 2+4+8+16+32+64 \right )\div 6 = 126 \div 6 = 21$

Compare your answer with the correct one above

Question

Consider the data set $\left \{ 20, 30, 30, 40, 40, 40, 40, 50, 50, 60, \square \right \}$

Which of the following elements replaces the box to make 42 the mean of the data set?

Answer

For the mean of the eleven data elements to be 42, their sum divided by 11 must be 42. Equivalently, the sum of the elements must be $42 \times 11 = 462$ .

The sum of the ten known elements is

Therefore, the unknown element must be

Compare your answer with the correct one above

Question

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Answer

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Compare your answer with the correct one above

Question

Give the mean of the following eight scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68 \right \}$

Answer

Divide the sum of the scores by eight:

$\frac{ 61+ 67+80+72+76+73+90+ 68}{8} = \frac{ 587}{8} = 73.375$

Compare your answer with the correct one above

Question

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Answer

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Compare your answer with the correct one above

Question

Consider the data set $\left \{ 20, 30, 30, 40, 40, 40, 40, 50, 50, 60, \square \right \}$

Which of the following elements replaces the box to make 42 the mean of the data set?

Answer

For the mean of the eleven data elements to be 42, their sum divided by 11 must be 42. Equivalently, the sum of the elements must be $42 \times 11 = 462$ .

The sum of the ten known elements is

Therefore, the unknown element must be

Compare your answer with the correct one above

Question

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Answer

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Compare your answer with the correct one above

Question

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Answer

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Compare your answer with the correct one above

Question

Give the mean of the following eight scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68 \right \}$

Answer

Divide the sum of the scores by eight:

$\frac{ 61+ 67+80+72+76+73+90+ 68}{8} = \frac{ 587}{8} = 73.375$

Compare your answer with the correct one above

Question

Give the mean of the data set $\left \{ 2, 4, 8, 16, 32, 64\right \}$

Answer

There are six elements, so to find the mean, add the elements and divide by six:

$\left ( 2+4+8+16+32+64 \right )\div 6 = 126 \div 6 = 21$

Compare your answer with the correct one above

Question

Give the mean of the following nine scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68, 70 \right \}$

Answer

Divide the sum of the scores by nine:

$\frac{ 61 + 67+ 80+ 72+ 76+73+90+68+70}{9} = \frac{ 657}{9} = 73$

Compare your answer with the correct one above

Question

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Answer

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Compare your answer with the correct one above

Question

Give the mean of the following eight scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68 \right \}$

Answer

Divide the sum of the scores by eight:

$\frac{ 61+ 67+80+72+76+73+90+ 68}{8} = \frac{ 587}{8} = 73.375$

Compare your answer with the correct one above

Question

Consider the data set: $\left \{ 13, 18, 20, 22, 24, 29, 30, 36\right \}$

What is the difference between the mean of this set and the median of this set?

Answer

To get the mean, add the numbers and divide by 8:

$\left ( 13+ 18+ 20+ 22+ 24+ 29+ 30+ 36 \right )\div 8 = 192 \div 8 = 24$

To get the median, find the mean of the fourth- and fifth-highest elements (the ones in the middle):

$(22 + 24) \div 2 = 46 \div 2 = 23$

The difference is

Compare your answer with the correct one above

Question

Consider the data set: $\left \{ 13, 18, 20, 22, 24, 29, 30, 36\right \}$

What is the difference between the mean of this set and the median of this set?

Answer

To get the mean, add the numbers and divide by 8:

$\left ( 13+ 18+ 20+ 22+ 24+ 29+ 30+ 36 \right )\div 8 = 192 \div 8 = 24$

To get the median, find the mean of the fourth- and fifth-highest elements (the ones in the middle):

$(22 + 24) \div 2 = 46 \div 2 = 23$

The difference is

Compare your answer with the correct one above

Question

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Answer

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Compare your answer with the correct one above

Question

Give the mean of the following nine scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68, 70 \right \}$

Answer

Divide the sum of the scores by nine:

$\frac{ 61 + 67+ 80+ 72+ 76+73+90+68+70}{9} = \frac{ 657}{9} = 73$

Compare your answer with the correct one above

Tap the card to reveal the answer

Mean - ISEE Middle Level Quantitative Reasoning

Give the mean of the data set (nearest tenth, if applicable):

Add the six elements and divide the sum by 6:

Give the mean of the data set

There are six elements, so to find the mean, add the elements and divide by six:

Give the mean of the following nine scores:

Divide the sum of the scores by nine:

Give the mean of the data set

There are six elements, so to find the mean, add the elements and divide by six:

Consider the data set Which of the following elements replaces the box to make 42 the mean of the data set?

For the mean of the eleven data elements to be 42, their sum divided by 11 must be 42. Equivalently, the sum of the elements must be . The sum of the ten known elements is Therefore, the unknown element must be

Give the mean of the following data set:

Since there are 16 elements, divide their sum by 16 to get the mean:

Give the mean of the following eight scores:

Divide the sum of the scores by eight:

Give the mean of the following data set:

Since there are 16 elements, divide their sum by 16 to get the mean:

Consider the data set Which of the following elements replaces the box to make 42 the mean of the data set?

For the mean of the eleven data elements to be 42, their sum divided by 11 must be 42. Equivalently, the sum of the elements must be . The sum of the ten known elements is Therefore, the unknown element must be

Give the mean of the following data set:

Since there are 16 elements, divide their sum by 16 to get the mean:

Give the mean of the following data set:

Since there are 16 elements, divide their sum by 16 to get the mean:

Give the mean of the following eight scores:

Divide the sum of the scores by eight:

Give the mean of the data set

There are six elements, so to find the mean, add the elements and divide by six:

Give the mean of the following nine scores:

Divide the sum of the scores by nine:

Give the mean of the following data set:

Since there are 16 elements, divide their sum by 16 to get the mean:

Give the mean of the following eight scores:

Divide the sum of the scores by eight:

Consider the data set: What is the difference between the mean of this set and the median of this set?

To get the mean, add the numbers and divide by 8: To get the median, find the mean of the fourth- and fifth-highest elements (the ones in the middle): The difference is

Consider the data set: What is the difference between the mean of this set and the median of this set?

To get the mean, add the numbers and divide by 8: To get the median, find the mean of the fourth- and fifth-highest elements (the ones in the middle): The difference is

Give the mean of the following data set:

Since there are 16 elements, divide their sum by 16 to get the mean:

Give the mean of the following nine scores:

Divide the sum of the scores by nine:

Give the mean of the data set (nearest tenth, if applicable):

$\left \{ 56,78,98,85,77,73 \right \}$

Add the six elements and divide the sum by 6:

$467 \div 6 \approx 77.8$

Give the mean of the data set $\left \{ 2, 4, 8, 16, 32, 64\right \}$

There are six elements, so to find the mean, add the elements and divide by six:

$\left ( 2+4+8+16+32+64 \right )\div 6 = 126 \div 6 = 21$

Give the mean of the following nine scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68, 70 \right \}$

Divide the sum of the scores by nine:

$\frac{ 61 + 67+ 80+ 72+ 76+73+90+68+70}{9} = \frac{ 657}{9} = 73$

Give the mean of the data set $\left \{ 2, 4, 8, 16, 32, 64\right \}$

There are six elements, so to find the mean, add the elements and divide by six:

$\left ( 2+4+8+16+32+64 \right )\div 6 = 126 \div 6 = 21$

Consider the data set $\left \{ 20, 30, 30, 40, 40, 40, 40, 50, 50, 60, \square \right \}$

Which of the following elements replaces the box to make 42 the mean of the data set?

For the mean of the eleven data elements to be 42, their sum divided by 11 must be 42. Equivalently, the sum of the elements must be $42 \times 11 = 462$ .

The sum of the ten known elements is

Therefore, the unknown element must be

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Give the mean of the following eight scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68 \right \}$

Divide the sum of the scores by eight:

$\frac{ 61+ 67+80+72+76+73+90+ 68}{8} = \frac{ 587}{8} = 73.375$

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Consider the data set $\left \{ 20, 30, 30, 40, 40, 40, 40, 50, 50, 60, \square \right \}$

Which of the following elements replaces the box to make 42 the mean of the data set?

For the mean of the eleven data elements to be 42, their sum divided by 11 must be 42. Equivalently, the sum of the elements must be $42 \times 11 = 462$ .

The sum of the ten known elements is

Therefore, the unknown element must be

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Give the mean of the following eight scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68 \right \}$

Divide the sum of the scores by eight:

$\frac{ 61+ 67+80+72+76+73+90+ 68}{8} = \frac{ 587}{8} = 73.375$

Give the mean of the data set $\left \{ 2, 4, 8, 16, 32, 64\right \}$

There are six elements, so to find the mean, add the elements and divide by six:

$\left ( 2+4+8+16+32+64 \right )\div 6 = 126 \div 6 = 21$

Give the mean of the following nine scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68, 70 \right \}$

Divide the sum of the scores by nine:

$\frac{ 61 + 67+ 80+ 72+ 76+73+90+68+70}{9} = \frac{ 657}{9} = 73$

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Give the mean of the following eight scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68 \right \}$

Divide the sum of the scores by eight:

$\frac{ 61+ 67+80+72+76+73+90+ 68}{8} = \frac{ 587}{8} = 73.375$

Consider the data set: $\left \{ 13, 18, 20, 22, 24, 29, 30, 36\right \}$

What is the difference between the mean of this set and the median of this set?

To get the mean, add the numbers and divide by 8:

$\left ( 13+ 18+ 20+ 22+ 24+ 29+ 30+ 36 \right )\div 8 = 192 \div 8 = 24$

To get the median, find the mean of the fourth- and fifth-highest elements (the ones in the middle):

$(22 + 24) \div 2 = 46 \div 2 = 23$

The difference is

Consider the data set: $\left \{ 13, 18, 20, 22, 24, 29, 30, 36\right \}$

What is the difference between the mean of this set and the median of this set?

To get the mean, add the numbers and divide by 8:

$\left ( 13+ 18+ 20+ 22+ 24+ 29+ 30+ 36 \right )\div 8 = 192 \div 8 = 24$

To get the median, find the mean of the fourth- and fifth-highest elements (the ones in the middle):

$(22 + 24) \div 2 = 46 \div 2 = 23$

The difference is

Give the mean of the following data set:

$\left \{1, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 9, 10 \right \}$

Since there are 16 elements, divide their sum by 16 to get the mean:

$(1+ 2+ 3+ 3+ 4+ 4+ 4+ 5+ 5+ 6+ 6+ 6+ 6+ 7+ 9+ 10) \div 16 = 81 \div 16 = 5.0625$

Give the mean of the following nine scores:

$\left \{ 61, 67, 80, 72, 76, 73, 90, 68, 70 \right \}$

Divide the sum of the scores by nine:

$\frac{ 61 + 67+ 80+ 72+ 76+73+90+68+70}{9} = \frac{ 657}{9} = 73$