Coordinate Geometry - GRE Quantitative Reasoning
Card 1 of 936
What is the slope of the line represented by the equation
?
What is the slope of the line represented by the equation ?
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To rearrange the equation into a
format, you want to isolate the
so that it is the sole variable, without a coefficient, on one side of the equation.
First, add
to both sides to get
.
Then, divide both sides by 6 to get
.
If you divide each part of the numerator by 6, you get
. This is in a
form, and the
is equal to
, which is reduced down to
for the correct answer.
To rearrange the equation into a format, you want to isolate the
so that it is the sole variable, without a coefficient, on one side of the equation.
First, add to both sides to get
.
Then, divide both sides by 6 to get .
If you divide each part of the numerator by 6, you get . This is in a
form, and the
is equal to
, which is reduced down to
for the correct answer.
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What is the slope of the line
?
What is the slope of the line ?
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To find the slope, put the equation in slope-intercept form
. In this case we have
, which indicates that the slope is
.
To find the slope, put the equation in slope-intercept form . In this case we have
, which indicates that the slope is
.
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What is the distance between
and
?
What is the distance between and
?
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distance2 = (_x_2 – _x_1)2 + (_y_2 – _y_1)2 + (_z_2 – _z_1)2
= (4 – 2)2 + (6 – 3)2 + (5 – 4)2
= 22 + 32 + 12
= 14
distance = √14
distance2 = (_x_2 – _x_1)2 + (_y_2 – _y_1)2 + (_z_2 – _z_1)2
= (4 – 2)2 + (6 – 3)2 + (5 – 4)2
= 22 + 32 + 12
= 14
distance = √14
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What is the slope of a line running through points
and
?
What is the slope of a line running through points and
?
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The slope is equal to the difference between the y-coordinates divided by the difference between the x-coordinates.

Use the give points in this formula to calculate the slope.

The slope is equal to the difference between the y-coordinates divided by the difference between the x-coordinates.
Use the give points in this formula to calculate the slope.
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What is the slope of the equation
?
What is the slope of the equation ?
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To find the slope of a line, you should convert an equation to the slope-intercept form. In this case, the equation would be
, which means the slope is
.
To find the slope of a line, you should convert an equation to the slope-intercept form. In this case, the equation would be , which means the slope is
.
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What is the slope of a line defined by the equation:

What is the slope of a line defined by the equation:
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A question like this is actually rather easy. All you need to do is rewrite the equation in slope intercept form, that is:

Therefore, begin to simplify:

Becomes...

Then...

Finally, divide both sides by
:

The coefficient for the
term is your slope: 
A question like this is actually rather easy. All you need to do is rewrite the equation in slope intercept form, that is:
Therefore, begin to simplify:
Becomes...
Then...
Finally, divide both sides by :
The coefficient for the term is your slope:
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Which of the following could be an equation for the red line pictured above?

Which of the following could be an equation for the red line pictured above?
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There are two key facts to register about this drawing. First, the line clearly has a negative slope, given that it runs "downhill" when you look at it from left to right. Secondly, it has a positive y-intercept. Therefore, you know that the coefficient for the
term must be negative, and the numerical coefficient for the y-intercept must be positive. This only occurs in the equation
. Therefore, this is the only viable option.
There are two key facts to register about this drawing. First, the line clearly has a negative slope, given that it runs "downhill" when you look at it from left to right. Secondly, it has a positive y-intercept. Therefore, you know that the coefficient for the term must be negative, and the numerical coefficient for the y-intercept must be positive. This only occurs in the equation
. Therefore, this is the only viable option.
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There is a line defined by two end-points,
and
. The midpoint between these two points is
. What is the value of the point
?
There is a line defined by two end-points, and
. The midpoint between these two points is
. What is the value of the point
?
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Recall that to find the midpoint of two points
and
, you use the equation:
.
(It is just like finding the average of the two points, really.)
So, for our equation, we know the following:

You merely need to solve each coordinate for its respective value.



Then, for the y-coordinate:



Therefore, our other point is: 
Recall that to find the midpoint of two points and
, you use the equation:
.
(It is just like finding the average of the two points, really.)
So, for our equation, we know the following:
You merely need to solve each coordinate for its respective value.
Then, for the y-coordinate:
Therefore, our other point is:
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There is a line defined by two end-points,
and
. The midpoint between these two points is
. What is the value of the point
?
There is a line defined by two end-points, and
. The midpoint between these two points is
. What is the value of the point
?
Tap to reveal answer
Recall that to find the midpoint of two points
and
, you use the equation:
.
(It is just like finding the average of the two points, really.)
So, for our equation, we know the following:

You merely need to solve each coordinate for its respective value.



Then, for the y-coordinate:



Therefore, our other point is: 
Recall that to find the midpoint of two points and
, you use the equation:
.
(It is just like finding the average of the two points, really.)
So, for our equation, we know the following:
You merely need to solve each coordinate for its respective value.
Then, for the y-coordinate:
Therefore, our other point is:
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Consider the lines described by the following two equations:
4y = 3x2
3y = 4x2
Find the vertical distance between the two lines at the points where x = 6.
Consider the lines described by the following two equations:
4y = 3x2
3y = 4x2
Find the vertical distance between the two lines at the points where x = 6.
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Since the vertical coordinates of each point are given by y, solve each equation for y and plug in 6 for x, as follows:

Taking the difference of the resulting y -values give the vertical distance between the points (6,27) and (6,48), which is 21.
Since the vertical coordinates of each point are given by y, solve each equation for y and plug in 6 for x, as follows:

Taking the difference of the resulting y -values give the vertical distance between the points (6,27) and (6,48), which is 21.
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Solve the following system of equations:
–2x + 3y = 10
2x + 5y = 6
Solve the following system of equations:
–2x + 3y = 10
2x + 5y = 6
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Since we have –2x and +2x in the equations, it makes sense to add the equations together to give 8y = 16 yielding y = 2. Then we substitute y = 2 into one of the original equations to get x = –2. So the solution to the system of equations is (–2, 2)
Since we have –2x and +2x in the equations, it makes sense to add the equations together to give 8y = 16 yielding y = 2. Then we substitute y = 2 into one of the original equations to get x = –2. So the solution to the system of equations is (–2, 2)
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Find the point where the line y = .25(x – 20) + 12 crosses the x-axis.
Find the point where the line y = .25(x – 20) + 12 crosses the x-axis.
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When the line crosses the x-axis, the y-coordinate is 0. Substitute 0 into the equation for y and solve for x.
.25(x – 20) + 12 = 0
.25_x_ – 5 = –12
.25_x_ = –7
x = –28
The answer is the point (–28,0).
When the line crosses the x-axis, the y-coordinate is 0. Substitute 0 into the equation for y and solve for x.
.25(x – 20) + 12 = 0
.25_x_ – 5 = –12
.25_x_ = –7
x = –28
The answer is the point (–28,0).
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What is the slope of the line perpendicular to the line given by the equation
6x – 9y +14 = 0
What is the slope of the line perpendicular to the line given by the equation
6x – 9y +14 = 0
Tap to reveal answer
First rearrange the equation so that it is in slope-intercept form, resulting in y=2/3 x + 14/9. The slope of this line is 2/3, so the slope of the line perpendicular will have the opposite reciprocal as a slope, which is -3/2.
First rearrange the equation so that it is in slope-intercept form, resulting in y=2/3 x + 14/9. The slope of this line is 2/3, so the slope of the line perpendicular will have the opposite reciprocal as a slope, which is -3/2.
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What is the slope of the line perpendicular to the line represented by the equation y = -2x+3?
What is the slope of the line perpendicular to the line represented by the equation y = -2x+3?
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Perpendicular lines have slopes that are the opposite of the reciprocal of each other. In this case, the slope of the first line is -2. The reciprocal of -2 is -1/2, so the opposite of the reciprocal is therefore 1/2.
Perpendicular lines have slopes that are the opposite of the reciprocal of each other. In this case, the slope of the first line is -2. The reciprocal of -2 is -1/2, so the opposite of the reciprocal is therefore 1/2.
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What is the distance between the two points, (1,1) and (7,9)?
What is the distance between the two points, (1,1) and (7,9)?
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distance2 = (_x_2 – _x_1)2 + (_y_2 – _y_1)2
Looking at the two order pairs given, _x_1 = 1, _y_1 = 1, _x_2 = 7, _y_2 = 9.
distance2 = (7 – 1)2 + (9 – 1)2 = 62 + 82 = 100
distance = 10
distance2 = (_x_2 – _x_1)2 + (_y_2 – _y_1)2
Looking at the two order pairs given, _x_1 = 1, _y_1 = 1, _x_2 = 7, _y_2 = 9.
distance2 = (7 – 1)2 + (9 – 1)2 = 62 + 82 = 100
distance = 10
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What is the other endpoint of a line segment with one point that is
and a midpoint of
?
What is the other endpoint of a line segment with one point that is and a midpoint of
?
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Recall that the midpoint formula is like finding the average of the
and
values for two points. For two points
and
, it is:

For our points, we are looking for
. We know:

We can solve for each of these coordinates separately:
X-Coordinate



Y-Coordinate:



Therefore, our point is 
Recall that the midpoint formula is like finding the average of the and
values for two points. For two points
and
, it is:
For our points, we are looking for . We know:
We can solve for each of these coordinates separately:
X-Coordinate
Y-Coordinate:
Therefore, our point is
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What is the slope
of a line passing through the point
, if it is defined by:
?
What is the slope of a line passing through the point
, if it is defined by:
?
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Since the equation is defined as it is, you know the y-intercept is
. This is the point
. To find the slope of the line, you merely need to use the two points that you have and find the equation:

Since the equation is defined as it is, you know the y-intercept is . This is the point
. To find the slope of the line, you merely need to use the two points that you have and find the equation:
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If the coordinates (3, 14) and (_–_5, 15) are on the same line, what is the equation of the line?
If the coordinates (3, 14) and (_–_5, 15) are on the same line, what is the equation of the line?
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First solve for the slope of the line, m using y=mx+b
m = (y2 – y1) / (x2 – x1)
= (15 – 14) / (_–_5 _–_3)
= (1 )/( _–_8)
=_–_1/8
y = –(1/8)x + b
Now, choose one of the coordinates and solve for b:
14 = –(1/8)3 + b
14 = _–_3/8 + b
b = 14 + (3/8)
b = 14.375
y = –(1/8)x + 14.375
First solve for the slope of the line, m using y=mx+b
m = (y2 – y1) / (x2 – x1)
= (15 – 14) / (_–_5 _–_3)
= (1 )/( _–_8)
=_–_1/8
y = –(1/8)x + b
Now, choose one of the coordinates and solve for b:
14 = –(1/8)3 + b
14 = _–_3/8 + b
b = 14 + (3/8)
b = 14.375
y = –(1/8)x + 14.375
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Which of the following is a line perpendicular to the line passing through
and
?
Which of the following is a line perpendicular to the line passing through and
?
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To find if something is perpendicular, you need to first know the slope of your given line. Based on your points, this is easy. Recall that slope is merely:

This is:

Since a perpendicular line has a slope that is both opposite in sign and reciprocal, you need to choose a line with a slope of
. The only possible option is, therefore, 
To find if something is perpendicular, you need to first know the slope of your given line. Based on your points, this is easy. Recall that slope is merely:
This is:
Since a perpendicular line has a slope that is both opposite in sign and reciprocal, you need to choose a line with a slope of . The only possible option is, therefore,
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What is the equation of the line passing through (–1,5) and the upper-right corner of a square with a center at the origin and a perimeter of 22?
What is the equation of the line passing through (–1,5) and the upper-right corner of a square with a center at the origin and a perimeter of 22?
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If the square has a perimeter of 22, each side is 22/4 or 5.5. This means that the upper-right corner is (2.75, 2.75)—remember that each side will be "split in half" by the x and y axes.
Using the two points we have, we can ascertain our line's equation by using the point-slope formula. Let us first get our slope:
m = rise/run = (2.75 – 5)/(2.75 + 1) = –2.25/3.75 = –(9/4)/(15/4) = –9/15 = –3/5.
The point-slope form is: y – y0 = m(x – x0). Based on our data this is: y – 5 = (–3/5)(x + 1); Simplifying, we get: y = (–3/5)x – (3/5) + 5; y = (–3/5)x + 22/5
If the square has a perimeter of 22, each side is 22/4 or 5.5. This means that the upper-right corner is (2.75, 2.75)—remember that each side will be "split in half" by the x and y axes.
Using the two points we have, we can ascertain our line's equation by using the point-slope formula. Let us first get our slope:
m = rise/run = (2.75 – 5)/(2.75 + 1) = –2.25/3.75 = –(9/4)/(15/4) = –9/15 = –3/5.
The point-slope form is: y – y0 = m(x – x0). Based on our data this is: y – 5 = (–3/5)(x + 1); Simplifying, we get: y = (–3/5)x – (3/5) + 5; y = (–3/5)x + 22/5
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