Decimals - GRE Quantitative Reasoning
Card 1 of 720
Write
in scientific notation.
Write in scientific notation.
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We want to move the decimal point to the place just after the first non-zero number, in this case 6, and then drop all of the non-significant zeros. We need to move the decimal point five spaces to the right, so our exponent should be negative. If the decimal had moved left, we would have had a positive exponent.
In this case we get 6.009 * 10–5.
We want to move the decimal point to the place just after the first non-zero number, in this case 6, and then drop all of the non-significant zeros. We need to move the decimal point five spaces to the right, so our exponent should be negative. If the decimal had moved left, we would have had a positive exponent.
In this case we get 6.009 * 10–5.
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find 0.72
find 0.72
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0.7 * 0.7 = 0.49
Trick: do the numbers without the decimals (7*7)
49; move the decimal of the answer the total number of spaces per each number (one for each 0.7)
0.49
0.7 * 0.7 = 0.49
Trick: do the numbers without the decimals (7*7)
49; move the decimal of the answer the total number of spaces per each number (one for each 0.7)
0.49
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Quantitative Comparison: Compare Quantity A and Quantity B, using additional information centered above the two quantities if such information is given.
10 < n < 15
Quantity A Quantity B
7/13 4/n
Quantitative Comparison: Compare Quantity A and Quantity B, using additional information centered above the two quantities if such information is given.
10 < n < 15
Quantity A Quantity B
7/13 4/n
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To determine which quantity is greater, we must first determine the range of potential values for Quantity B. Let's call this quantity m. This is most efficiently done by dividing 4 by the highest and lowest possible values for n.
4/10 = 0.4
4/15 = 0.267
So the possible values for m are 0.267 < m < 0.4
Now let's find the value for 7/13, to make comparison easier.
7/13 = 0.538
Given this, no matter what the value of n is, 7/13 will still be a higher proportion, so Quantity B is greater.
To determine which quantity is greater, we must first determine the range of potential values for Quantity B. Let's call this quantity m. This is most efficiently done by dividing 4 by the highest and lowest possible values for n.
4/10 = 0.4
4/15 = 0.267
So the possible values for m are 0.267 < m < 0.4
Now let's find the value for 7/13, to make comparison easier.
7/13 = 0.538
Given this, no matter what the value of n is, 7/13 will still be a higher proportion, so Quantity B is greater.
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Choose the answer below which best expresses the following decimal as a fraction (choose the answer which has been reduced/simplified the most):

Choose the answer below which best expresses the following decimal as a fraction (choose the answer which has been reduced/simplified the most):
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To convert from a decimal to a fraction, simply put the digits over one followed by a number of zeroes equal to the number of digits:

The zero in front of the
can be removed, leaving:
, which can be reducted to:

To convert from a decimal to a fraction, simply put the digits over one followed by a number of zeroes equal to the number of digits:
The zero in front of the can be removed, leaving:
, which can be reducted to:
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find 0.72
find 0.72
Tap to reveal answer
0.7 * 0.7 = 0.49
Trick: do the numbers without the decimals (7*7)
49; move the decimal of the answer the total number of spaces per each number (one for each 0.7)
0.49
0.7 * 0.7 = 0.49
Trick: do the numbers without the decimals (7*7)
49; move the decimal of the answer the total number of spaces per each number (one for each 0.7)
0.49
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0.3 < 1/3
4 > √17
1/2 < 1/8
–|–6| = 6
Which of the above statements is true?
0.3 < 1/3
4 > √17
1/2 < 1/8
–|–6| = 6
Which of the above statements is true?
Tap to reveal answer
The best approach to this equation is to evaluate each of the equations and inequalities. The absolute value of –6 is 6, but the opposite of that value indicated by the “–“ is –6, which does not equal 6.
1/2 is 0.5, while 1/8 is 0.125 so 0.5 > 0.125.
√17 has to be slightly more than the √16, which equals 4, so“>” should be “<”.
Finally, the fraction 1/3 has repeating 3s which makes it larger than 3/10 so it is true.
The best approach to this equation is to evaluate each of the equations and inequalities. The absolute value of –6 is 6, but the opposite of that value indicated by the “–“ is –6, which does not equal 6.
1/2 is 0.5, while 1/8 is 0.125 so 0.5 > 0.125.
√17 has to be slightly more than the √16, which equals 4, so“>” should be “<”.
Finally, the fraction 1/3 has repeating 3s which makes it larger than 3/10 so it is true.
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Solve for
:

Solve for :
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To add decimals, simply treat them like you would any other number. Any time two of the digits in a particular place (i.e. tenths, hundredths, thousandths) add up to more than ten, you have to carry the one to the next greatest column. Therefore:

So
.
To add decimals, simply treat them like you would any other number. Any time two of the digits in a particular place (i.e. tenths, hundredths, thousandths) add up to more than ten, you have to carry the one to the next greatest column. Therefore:
So .
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Solve for
:

Solve for :
Tap to reveal answer
To solve this problem, subtract
from both sides of the eqution, 
Therefore,
.
If you're having trouble subtracting the decimal, mutliply both numbers by
followed by a number of zeroes equal to the number of decimal places. Then subtract, then divide both numbers by the number you multiplied them by.
To solve this problem, subtract from both sides of the eqution,
Therefore, .
If you're having trouble subtracting the decimal, mutliply both numbers by followed by a number of zeroes equal to the number of decimal places. Then subtract, then divide both numbers by the number you multiplied them by.
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Solve for
:

Solve for :
Tap to reveal answer
To solve, you need to do some algebra:

Isolate x by adding the 4.150 to both sides of the equation.


Then add the decimals. If you have trouble adding decimals, an effective method is to place one decimal over the other, and add the digits one at a time. Remember to carry every time the digits in a given place add up to more than
.

To solve, you need to do some algebra:
Isolate x by adding the 4.150 to both sides of the equation.
Then add the decimals. If you have trouble adding decimals, an effective method is to place one decimal over the other, and add the digits one at a time. Remember to carry every time the digits in a given place add up to more than .
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Solve for
:

Solve for :
Tap to reveal answer
To solve for
, first add
to both sides of the equation, so that you isolate the variable:


Then, add your decimals, and remember that
.

To solve for , first add
to both sides of the equation, so that you isolate the variable:
Then, add your decimals, and remember that .
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Solve for
:

Solve for :
Tap to reveal answer
To solve, first add
to both sides of your equation, so you isolate the variable:


Then add the decimals together:

To solve, first add to both sides of your equation, so you isolate the variable:
Then add the decimals together:
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Solve for
:

Solve for :
Tap to reveal answer
To solve, first add
to both sides of the equation:


Then add the decimals together:

To solve, first add to both sides of the equation:
Then add the decimals together:
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Solve for
:

Solve for :
Tap to reveal answer
To add decimals, simply treat them like you would any other number. Any time two of the digits in a particular place (i.e. tenths, hundredths, thousandths) add up to more than ten, you have to carry the one to the next greatest column. Therefore:

So
.
To add decimals, simply treat them like you would any other number. Any time two of the digits in a particular place (i.e. tenths, hundredths, thousandths) add up to more than ten, you have to carry the one to the next greatest column. Therefore:
So .
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Solve for
:

Solve for :
Tap to reveal answer
To solve this problem, subtract
from both sides of the eqution, 
Therefore,
.
If you're having trouble subtracting the decimal, mutliply both numbers by
followed by a number of zeroes equal to the number of decimal places. Then subtract, then divide both numbers by the number you multiplied them by.
To solve this problem, subtract from both sides of the eqution,
Therefore, .
If you're having trouble subtracting the decimal, mutliply both numbers by followed by a number of zeroes equal to the number of decimal places. Then subtract, then divide both numbers by the number you multiplied them by.
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Solve for
:

Solve for :
Tap to reveal answer
To solve, you need to do some algebra:

Isolate x by adding the 4.150 to both sides of the equation.


Then add the decimals. If you have trouble adding decimals, an effective method is to place one decimal over the other, and add the digits one at a time. Remember to carry every time the digits in a given place add up to more than
.

To solve, you need to do some algebra:
Isolate x by adding the 4.150 to both sides of the equation.
Then add the decimals. If you have trouble adding decimals, an effective method is to place one decimal over the other, and add the digits one at a time. Remember to carry every time the digits in a given place add up to more than .
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Solve for
:

Solve for :
Tap to reveal answer
To solve for
, first add
to both sides of the equation, so that you isolate the variable:


Then, add your decimals, and remember that
.

To solve for , first add
to both sides of the equation, so that you isolate the variable:
Then, add your decimals, and remember that .
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Solve for
:

Solve for :
Tap to reveal answer
To solve, first add
to both sides of your equation, so you isolate the variable:


Then add the decimals together:

To solve, first add to both sides of your equation, so you isolate the variable:
Then add the decimals together:
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Solve for
:

Solve for :
Tap to reveal answer
To solve, first add
to both sides of the equation:


Then add the decimals together:

To solve, first add to both sides of the equation:
Then add the decimals together:
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Solve for
:

Solve for :
Tap to reveal answer
To add decimals, simply treat them like you would any other number. Any time two of the digits in a particular place (i.e. tenths, hundredths, thousandths) add up to more than ten, you have to carry the one to the next greatest column. Therefore:

So
.
To add decimals, simply treat them like you would any other number. Any time two of the digits in a particular place (i.e. tenths, hundredths, thousandths) add up to more than ten, you have to carry the one to the next greatest column. Therefore:
So .
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Solve for
:

Solve for :
Tap to reveal answer
To solve this problem, subtract
from both sides of the eqution, 
Therefore,
.
If you're having trouble subtracting the decimal, mutliply both numbers by
followed by a number of zeroes equal to the number of decimal places. Then subtract, then divide both numbers by the number you multiplied them by.
To solve this problem, subtract from both sides of the eqution,
Therefore, .
If you're having trouble subtracting the decimal, mutliply both numbers by followed by a number of zeroes equal to the number of decimal places. Then subtract, then divide both numbers by the number you multiplied them by.
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