Diagrams - GMAT Quantitative
Card 0 of 160

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
Compare your answer with the correct one above

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
Compare your answer with the correct one above

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
Compare your answer with the correct one above

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
Compare your answer with the correct one above

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
Compare your answer with the correct one above

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
Compare your answer with the correct one above

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
Compare your answer with the correct one above

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
Compare your answer with the correct one above

Public domain map from The World Factbook, Central Intelligence Agency.
Flight 783 departs from Oslo, Norway when it is 7:12 AM there; it lands in Dallas when it is 10:37 AM there. How long did the flight take?
(Assume Daylight Savings Time is not in effect.)

Public domain map from The World Factbook, Central Intelligence Agency.
Flight 783 departs from Oslo, Norway when it is 7:12 AM there; it lands in Dallas when it is 10:37 AM there. How long did the flight take?
(Assume Daylight Savings Time is not in effect.)
Refer to the time zone differences printed at the top of the map. The time zone for Dallas is marked
; the time zone for all of Norway is marked
. This means that Oslo is
hours ahead of Dallas, so we need to adjust accordingly.
The flight took off when it was
in Oslo; if we subtract
, then we find that it took off when it was
in Dallas. Now subtract this from
:

Adjust by adding
to
:

The flight took
.
Refer to the time zone differences printed at the top of the map. The time zone for Dallas is marked ; the time zone for all of Norway is marked
. This means that Oslo is
hours ahead of Dallas, so we need to adjust accordingly.
The flight took off when it was in Oslo; if we subtract
, then we find that it took off when it was
in Dallas. Now subtract this from
:
Adjust by adding to
:
The flight took .
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Three candidates - Craig, Donna, and Elly - ran for student body president. By the rules, the candidate who wins more than half the ballots cast wins the election outright; if no candidate wins more than half, there must be a runoff between the two top vote-getters. You may assume that no other names were written in.
As can be seen in the figure above, which reflects the share of the vote each candidate won, there will be a runoff. Which two candidates will face each other?
Statement 1: Candidate C is Donna.
Statement 2: Craig won 528 votes.

Three candidates - Craig, Donna, and Elly - ran for student body president. By the rules, the candidate who wins more than half the ballots cast wins the election outright; if no candidate wins more than half, there must be a runoff between the two top vote-getters. You may assume that no other names were written in.
As can be seen in the figure above, which reflects the share of the vote each candidate won, there will be a runoff. Which two candidates will face each other?
Statement 1: Candidate C is Donna.
Statement 2: Craig won 528 votes.
From Statement 1 alone, it can be seen that Donna's share of the vote was the smallest of the three. Therefore, Craig and Elly were the top two votegetters, and they will face each other in the runoff.
Statement 2 alone provides insufficient information; without knowing the total number of voters, the share of the vote won by Craig (or any other candidate) cannot be determined from the number of votes Craig won.
From Statement 1 alone, it can be seen that Donna's share of the vote was the smallest of the three. Therefore, Craig and Elly were the top two votegetters, and they will face each other in the runoff.
Statement 2 alone provides insufficient information; without knowing the total number of voters, the share of the vote won by Craig (or any other candidate) cannot be determined from the number of votes Craig won.
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Light blue: Goodman
Orange: Ferris
Gray: Inman
Yellow: Jones
Dark blue: Harris
Refer to the diagram. If 3,145 people voted in the school board election, (the results of which are represented in the diagram), then approximately how many people voted for Inman?

Light blue: Goodman
Orange: Ferris
Gray: Inman
Yellow: Jones
Dark blue: Harris
Refer to the diagram. If 3,145 people voted in the school board election, (the results of which are represented in the diagram), then approximately how many people voted for Inman?
According to the legend, the gray sector represents the portion of the electorate who voted for Inman. This sector is about one-fifth of the circle, so, to find the best estimate of Inman's share of the vote, take one-fifth of 3,145 - or, equivalently, divide 3,145 by 5:

630 is the best estimate of the choices given.
According to the legend, the gray sector represents the portion of the electorate who voted for Inman. This sector is about one-fifth of the circle, so, to find the best estimate of Inman's share of the vote, take one-fifth of 3,145 - or, equivalently, divide 3,145 by 5:
630 is the best estimate of the choices given.
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Of the
people,
were either men or blonde or both. Therefore,
are non-blonde and non-men (women).

Of the people,
were either men or blonde or both. Therefore,
are non-blonde and non-men (women).
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The above table shows the results of a school election. According to the rules, the students who finish first, second, and third become President, Vice-President, and Secretary-Treasurer respectively. In the event of any tie, a runoff election will be held.
Who was elected Secretary-Treasurer?
The above table shows the results of a school election. According to the rules, the students who finish first, second, and third become President, Vice-President, and Secretary-Treasurer respectively. In the event of any tie, a runoff election will be held.
Who was elected Secretary-Treasurer?
Jones and Smith tied for third (87 each), so by the rules, there will be a runoff election for the office of Secretary-Treasurer between these two.
Jones and Smith tied for third (87 each), so by the rules, there will be a runoff election for the office of Secretary-Treasurer between these two.
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The above circle graph shows the results of a school election. According to the rules, the students who finish first, second, and third become President, Vice-President, and Secretary-Treasurer respectively. In the event of any tie, a runoff election will be held.
Who was elected Secretary-Treasurer?

The above circle graph shows the results of a school election. According to the rules, the students who finish first, second, and third become President, Vice-President, and Secretary-Treasurer respectively. In the event of any tie, a runoff election will be held.
Who was elected Secretary-Treasurer?
The third-largest portion of the graph is the gray portion, which represents Wells. Wells won the office of Secretary-Treasurer outright.
The third-largest portion of the graph is the gray portion, which represents Wells. Wells won the office of Secretary-Treasurer outright.
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The table below gives the population of the city of Renfrow for each of six census years.

Which decade saw a population decline?
The table below gives the population of the city of Renfrow for each of six census years.
Which decade saw a population decline?
The only census year in which Renfrow had fewer people than the previous one is 1970, so the correct choice is 1960-70.
The only census year in which Renfrow had fewer people than the previous one is 1970, so the correct choice is 1960-70.
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The table below gives the population of the city of Renfrow for each of six census years.

Which decade saw the greatest increase in population?
The table below gives the population of the city of Renfrow for each of six census years.
Which decade saw the greatest increase in population?
For each decade, we can subtract the population at the beginning of the decade from that at the end. We omit 1960-70 since there was a population decline.





1950-60 saw the greatest increase.
For each decade, we can subtract the population at the beginning of the decade from that at the end. We omit 1960-70 since there was a population decline.
1950-60 saw the greatest increase.
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The table below gives the population of the city of Renfrow for each of six census years.

The figures for subsequent years are not currently available but it is known that the increase over each decade since 1980 has been at least as great as the increase from 1970 to 1980. What was the minimum population in 2010?
The table below gives the population of the city of Renfrow for each of six census years.
The figures for subsequent years are not currently available but it is known that the increase over each decade since 1980 has been at least as great as the increase from 1970 to 1980. What was the minimum population in 2010?
The increase in population from 1970 to 1980 was
. Since each of the three ten-year growths from 1980 to 2010 was at least that much, the minimum population of Renfrow in 2010 was 
The increase in population from 1970 to 1980 was . Since each of the three ten-year growths from 1980 to 2010 was at least that much, the minimum population of Renfrow in 2010 was
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The above is the menu at Monorail Sandwich Shop.
Today, Monorail is running a special - buy three sandwiches and get a large soda free. A boss treats her employees to lunch; she orders three beef sandwiches, two turkey sandwiches, two ham sandwiches, and seven large sodas. There is no sales tax. If the boss hands the clerk a $100 bill, how much change will she get back?
The above is the menu at Monorail Sandwich Shop.
Today, Monorail is running a special - buy three sandwiches and get a large soda free. A boss treats her employees to lunch; she orders three beef sandwiches, two turkey sandwiches, two ham sandwiches, and seven large sodas. There is no sales tax. If the boss hands the clerk a $100 bill, how much change will she get back?
The boss orders seven sandwiches, so two of the sodas will be free. Therefore, she will pay for three beef sandwiches, two turkey sandwiches, two ham sandwiches, and five large sodas. Their total price:



The change from a $100 bill is
.
The boss orders seven sandwiches, so two of the sodas will be free. Therefore, she will pay for three beef sandwiches, two turkey sandwiches, two ham sandwiches, and five large sodas. Their total price:
The change from a $100 bill is
.
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The above is the menu at Monorail Sandwich Shop.
Today, Monorail is running a special - buy any two sandwiches and get an additonal sandwich of equal or lesser value for free, with a limit of two free sandwiches per customer per day.
A father wants to buy some sandwiches for his family. He orders two beef sandwiches, three chicken sandwiches, and four veggie sandwiches. Disregarding sales tax, what is the least possible amount he will pay for them?
The above is the menu at Monorail Sandwich Shop.
Today, Monorail is running a special - buy any two sandwiches and get an additonal sandwich of equal or lesser value for free, with a limit of two free sandwiches per customer per day.
A father wants to buy some sandwiches for his family. He orders two beef sandwiches, three chicken sandwiches, and four veggie sandwiches. Disregarding sales tax, what is the least possible amount he will pay for them?
In descending order of cost, he is ordering sandwiches that cost the following:

Note that the father will get one chicken sandwich free with the two beef sandwiches, and that he will get one veggie sandwich free with the other two chicken sandwiches. Therefore, he will pay for the other seven sandwiches:

In descending order of cost, he is ordering sandwiches that cost the following:
Note that the father will get one chicken sandwich free with the two beef sandwiches, and that he will get one veggie sandwich free with the other two chicken sandwiches. Therefore, he will pay for the other seven sandwiches:
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The above is the menu at Monorail Sandwich Shop.
Monorail is running a special today - for each sandwich you buy, you can purchase one large soda for ninety cents or get one small soda for free.
Kevin purchases three beef sandwiches, two large sodas, and two small sodas. Disregarding tax, how much will he pay?
The above is the menu at Monorail Sandwich Shop.
Monorail is running a special today - for each sandwich you buy, you can purchase one large soda for ninety cents or get one small soda for free.
Kevin purchases three beef sandwiches, two large sodas, and two small sodas. Disregarding tax, how much will he pay?
Kevin will pay $5.89 each for the three beef sandwiches. He will pay $0.90 for each of the two large sodas and get one of the small sodas for free; he will pay the full price of $1.09 for one small soda. Therefore, Kevin will pay

Kevin will pay $5.89 each for the three beef sandwiches. He will pay $0.90 for each of the two large sodas and get one of the small sodas for free; he will pay the full price of $1.09 for one small soda. Therefore, Kevin will pay
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