Diagrams - GMAT Quantitative
Card 1 of 160

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
Tap to reveal answer
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
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Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
Tap to reveal answer
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
← Didn't Know|Knew It →

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
Tap to reveal answer
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
← Didn't Know|Knew It →

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
Tap to reveal answer
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
← Didn't Know|Knew It →

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
Tap to reveal answer
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
← Didn't Know|Knew It →

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
Tap to reveal answer
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
← Didn't Know|Knew It →

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
Tap to reveal answer
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
← Didn't Know|Knew It →

Define the universal set
.
Define
to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?

Define the universal set .
Define to be the set of prime numbers,
to be the set of integers that end in 2, 5, or 8, and
. If each number in the universal set were to be placed in its correct region in the above Venn diagram, how many integers would lie in the gray region?
Tap to reveal answer
The integers that go into the gray region are those that do not fall into any of the three sets
,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in
. This leaves 30 so far:

Now we can eliminate nine integers from
- the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from
- 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
The integers that go into the gray region are those that do not fall into any of the three sets ,
, or
. We can eliminate the integers by taking the universal set and eliminating the elements that fall in any one of the three.
Out of the 50 integers from 1 to 50, we can eliminate the 20 that are in . This leaves 30 so far:
Now we can eliminate nine integers from - the ones that end in 2, 5, or 8. The 21 remaining numbers are
.
We now eliminate the primes from - 3, 7, 11, 13, 17, 19, 41, 43, 47. This leaves us with
,
a set with 12 elements.
← Didn't Know|Knew It →

The above table shows the results of a school election. According to the rules, the students who finish first, second, and third become President, Vice-President, and Secretary-Treasurer respectively. In the event of any tie, a runoff election will be held.
Who was elected Secretary-Treasurer?
The above table shows the results of a school election. According to the rules, the students who finish first, second, and third become President, Vice-President, and Secretary-Treasurer respectively. In the event of any tie, a runoff election will be held.
Who was elected Secretary-Treasurer?
Tap to reveal answer
Jones and Smith tied for third (87 each), so by the rules, there will be a runoff election for the office of Secretary-Treasurer between these two.
Jones and Smith tied for third (87 each), so by the rules, there will be a runoff election for the office of Secretary-Treasurer between these two.
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The above circle graph shows the results of a school election. According to the rules, the students who finish first, second, and third become President, Vice-President, and Secretary-Treasurer respectively. In the event of any tie, a runoff election will be held.
Who was elected Secretary-Treasurer?

The above circle graph shows the results of a school election. According to the rules, the students who finish first, second, and third become President, Vice-President, and Secretary-Treasurer respectively. In the event of any tie, a runoff election will be held.
Who was elected Secretary-Treasurer?
Tap to reveal answer
The third-largest portion of the graph is the gray portion, which represents Wells. Wells won the office of Secretary-Treasurer outright.
The third-largest portion of the graph is the gray portion, which represents Wells. Wells won the office of Secretary-Treasurer outright.
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Light blue: Goodman
Orange: Ferris
Gray: Inman
Yellow: Jones
Dark blue: Harris
Refer to the diagram. If 3,145 people voted in the school board election, (the results of which are represented in the diagram), then approximately how many people voted for Inman?

Light blue: Goodman
Orange: Ferris
Gray: Inman
Yellow: Jones
Dark blue: Harris
Refer to the diagram. If 3,145 people voted in the school board election, (the results of which are represented in the diagram), then approximately how many people voted for Inman?
Tap to reveal answer
According to the legend, the gray sector represents the portion of the electorate who voted for Inman. This sector is about one-fifth of the circle, so, to find the best estimate of Inman's share of the vote, take one-fifth of 3,145 - or, equivalently, divide 3,145 by 5:

630 is the best estimate of the choices given.
According to the legend, the gray sector represents the portion of the electorate who voted for Inman. This sector is about one-fifth of the circle, so, to find the best estimate of Inman's share of the vote, take one-fifth of 3,145 - or, equivalently, divide 3,145 by 5:
630 is the best estimate of the choices given.
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Of the
people,
were either men or blonde or both. Therefore,
are non-blonde and non-men (women).

Of the people,
were either men or blonde or both. Therefore,
are non-blonde and non-men (women).
← Didn't Know|Knew It →
The table below gives the population of the city of Renfrow for each of six census years.

Which decade saw a population decline?
The table below gives the population of the city of Renfrow for each of six census years.
Which decade saw a population decline?
Tap to reveal answer
The only census year in which Renfrow had fewer people than the previous one is 1970, so the correct choice is 1960-70.
The only census year in which Renfrow had fewer people than the previous one is 1970, so the correct choice is 1960-70.
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The table below gives the population of the city of Renfrow for each of six census years.

Which decade saw the greatest increase in population?
The table below gives the population of the city of Renfrow for each of six census years.
Which decade saw the greatest increase in population?
Tap to reveal answer
For each decade, we can subtract the population at the beginning of the decade from that at the end. We omit 1960-70 since there was a population decline.





1950-60 saw the greatest increase.
For each decade, we can subtract the population at the beginning of the decade from that at the end. We omit 1960-70 since there was a population decline.
1950-60 saw the greatest increase.
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The table below gives the population of the city of Renfrow for each of six census years.

The figures for subsequent years are not currently available but it is known that the increase over each decade since 1980 has been at least as great as the increase from 1970 to 1980. What was the minimum population in 2010?
The table below gives the population of the city of Renfrow for each of six census years.
The figures for subsequent years are not currently available but it is known that the increase over each decade since 1980 has been at least as great as the increase from 1970 to 1980. What was the minimum population in 2010?
Tap to reveal answer
The increase in population from 1970 to 1980 was
. Since each of the three ten-year growths from 1980 to 2010 was at least that much, the minimum population of Renfrow in 2010 was 
The increase in population from 1970 to 1980 was . Since each of the three ten-year growths from 1980 to 2010 was at least that much, the minimum population of Renfrow in 2010 was
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The above is the menu at Monorail Sandwich Shop.
Today, Monorail is running a special - buy three sandwiches and get a large soda free. A boss treats her employees to lunch; she orders three beef sandwiches, two turkey sandwiches, two ham sandwiches, and seven large sodas. There is no sales tax. If the boss hands the clerk a $100 bill, how much change will she get back?
The above is the menu at Monorail Sandwich Shop.
Today, Monorail is running a special - buy three sandwiches and get a large soda free. A boss treats her employees to lunch; she orders three beef sandwiches, two turkey sandwiches, two ham sandwiches, and seven large sodas. There is no sales tax. If the boss hands the clerk a $100 bill, how much change will she get back?
Tap to reveal answer
The boss orders seven sandwiches, so two of the sodas will be free. Therefore, she will pay for three beef sandwiches, two turkey sandwiches, two ham sandwiches, and five large sodas. Their total price:



The change from a $100 bill is
.
The boss orders seven sandwiches, so two of the sodas will be free. Therefore, she will pay for three beef sandwiches, two turkey sandwiches, two ham sandwiches, and five large sodas. Their total price:
The change from a $100 bill is
.
← Didn't Know|Knew It →

The above is the menu at Monorail Sandwich Shop.
Today, Monorail is running a special - buy any two sandwiches and get an additonal sandwich of equal or lesser value for free, with a limit of two free sandwiches per customer per day.
A father wants to buy some sandwiches for his family. He orders two beef sandwiches, three chicken sandwiches, and four veggie sandwiches. Disregarding sales tax, what is the least possible amount he will pay for them?
The above is the menu at Monorail Sandwich Shop.
Today, Monorail is running a special - buy any two sandwiches and get an additonal sandwich of equal or lesser value for free, with a limit of two free sandwiches per customer per day.
A father wants to buy some sandwiches for his family. He orders two beef sandwiches, three chicken sandwiches, and four veggie sandwiches. Disregarding sales tax, what is the least possible amount he will pay for them?
Tap to reveal answer
In descending order of cost, he is ordering sandwiches that cost the following:

Note that the father will get one chicken sandwich free with the two beef sandwiches, and that he will get one veggie sandwich free with the other two chicken sandwiches. Therefore, he will pay for the other seven sandwiches:

In descending order of cost, he is ordering sandwiches that cost the following:
Note that the father will get one chicken sandwich free with the two beef sandwiches, and that he will get one veggie sandwich free with the other two chicken sandwiches. Therefore, he will pay for the other seven sandwiches:
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The above is the menu at Monorail Sandwich Shop.
Monorail is running a special today - for each sandwich you buy, you can purchase one large soda for ninety cents or get one small soda for free.
Kevin purchases three beef sandwiches, two large sodas, and two small sodas. Disregarding tax, how much will he pay?
The above is the menu at Monorail Sandwich Shop.
Monorail is running a special today - for each sandwich you buy, you can purchase one large soda for ninety cents or get one small soda for free.
Kevin purchases three beef sandwiches, two large sodas, and two small sodas. Disregarding tax, how much will he pay?
Tap to reveal answer
Kevin will pay $5.89 each for the three beef sandwiches. He will pay $0.90 for each of the two large sodas and get one of the small sodas for free; he will pay the full price of $1.09 for one small soda. Therefore, Kevin will pay

Kevin will pay $5.89 each for the three beef sandwiches. He will pay $0.90 for each of the two large sodas and get one of the small sodas for free; he will pay the full price of $1.09 for one small soda. Therefore, Kevin will pay
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The above is the menu at Monorail Sandwich Shop. The sales tax is 8%, and with the purchase of two sandwiches, a customer gets one free soda of any size.
Charlie wants to purchase four turkey sandwiches. He only has $30 on him and he has no checks, debit cards, or credit cards. How many large sodas can he get with the sandwiches and stay within his budget?
The above is the menu at Monorail Sandwich Shop. The sales tax is 8%, and with the purchase of two sandwiches, a customer gets one free soda of any size.
Charlie wants to purchase four turkey sandwiches. He only has $30 on him and he has no checks, debit cards, or credit cards. How many large sodas can he get with the sandwiches and stay within his budget?
Tap to reveal answer
If
is the maximum price of the sandwiches before tax, then the price after tax is
. Charlie can spend at most $30 after sales tax of 8% is counted, so we can set up the equation:



The four turkey sandwiches cost
, leaving

to buy drinks.
buys one large soda.
, so
allows for the purchase of two. Also, with the four sandwiches, he gets two free sodas, so he can get a total of four sodas.
If is the maximum price of the sandwiches before tax, then the price after tax is
. Charlie can spend at most $30 after sales tax of 8% is counted, so we can set up the equation:
The four turkey sandwiches cost , leaving
to buy drinks.
buys one large soda.
, so
allows for the purchase of two. Also, with the four sandwiches, he gets two free sodas, so he can get a total of four sodas.
← Didn't Know|Knew It →
Five candidates ran for the office of student body president at Garfield High School. According to the rules, the student who gets the most votes wins the office, with ties resulting in a runoff. However, Garfield has an unusual rule that states that seniors' votes count double.
This table shows how freshmen, sophomores, and juniors voted:

This table shows how seniors voted:

Who won the election?
Five candidates ran for the office of student body president at Garfield High School. According to the rules, the student who gets the most votes wins the office, with ties resulting in a runoff. However, Garfield has an unusual rule that states that seniors' votes count double.
This table shows how freshmen, sophomores, and juniors voted:
This table shows how seniors voted:
Who won the election?
Tap to reveal answer
For each candidate, add the number of freshman, sophomore, and junior votes to twice the number of senior votes:

Jones won the election.
For each candidate, add the number of freshman, sophomore, and junior votes to twice the number of senior votes:
Jones won the election.
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