Geometric Measurement and Dimension: Informal Argument for Volume of a Sphere (CCSS.G-GMD.2)
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Common Core High School Geometry › Geometric Measurement and Dimension: Informal Argument for Volume of a Sphere (CCSS.G-GMD.2)
A cone and a cylinder have the same radius r and height h. How does the volume of the cone compare to the volume of the cylinder?
Equal to the cylinder's volume
One-third of the cylinder's volume
One-half of the cylinder's volume
Two-thirds of the cylinder's volume
Explanation
Formulas: $V_{\text{cyl}}=\pi r^2 h$, $V_{\text{cone}}=\tfrac{1}{3}\pi r^2 h$, so the cone is one-third of the cylinder. By Cavalieri's principle, the cone's cross-sections scale so that its "average" cross-sectional area is $\tfrac{1}{3}$ of the cylinder's. The $\tfrac{1}{2}$ distractor confuses the cone's factor with a common but incorrect guess.
A sphere of radius r and a cylinder with radius r and height 2r are compared. How does the volume of the sphere compare to the volume of the cylinder?
They are equal
The sphere is greater than the cylinder
The sphere is one-half of the cylinder
The sphere is two-thirds of the cylinder
Explanation
Formulas: $V_{\text{sphere}}=\tfrac{4}{3}\pi r^3$ and $V_{\text{cyl}}=\pi r^2(2r)=2\pi r^3$, so $\tfrac{V_{\text{sphere}}}{V_{\text{cyl}}}=\tfrac{4/3}{2}=\tfrac{2}{3}$. By Cavalieri's principle, slicing shows the sphere's cross-sections pair with those of a cone to match the cylinder, yielding the $\tfrac{2}{3}$ ratio. The "equal" and "greater" choices contradict these area-by-slices comparisons.
For a sphere, if the radius doubles, how does the volume change?
It multiplies by 8
It multiplies by 4
It doubles
It triples
Explanation
Sphere volume scales with $r^3$: $V=\tfrac{4}{3}\pi r^3$. Doubling $r$ multiplies volume by $2^3=8$. By Cavalieri's principle, all cross-sectional areas scale with $r^2$ and the overall depth with $r$, giving a cubic scaling. The $\times 4$ distractor mistakes area scaling for volume scaling.
For a cylinder, if the radius is tripled and the height is doubled, by what factor does the volume increase?
12
9
18
6
Explanation
Cylinder volume $V=\pi r^2 h$. Tripling $r$ multiplies cross-sectional area by $3^2=9$, and doubling $h$ multiplies by $2$, for a total factor $9\cdot 2=18$. By Cavalieri's principle, volume equals area of cross-sections times height, so area and height scalings multiply.
A hemisphere of radius r and a cone with radius r and height r are compared. How does the volume of the hemisphere compare to the volume of the cone?
Equal to the cone's volume
Twice the cone's volume
Three times the cone's volume
Half the cone's volume
Explanation
Formulas: $V_{\text{hemi}}=\tfrac{1}{2}\cdot \tfrac{4}{3}\pi r^3=\tfrac{2}{3}\pi r^3$ and $V_{\text{cone}}=\tfrac{1}{3}\pi r^2(r)=\tfrac{1}{3}\pi r^3$. Thus the hemisphere is twice the cone. By Cavalieri's principle, the hemisphere's slices average to double the cone's slices at matching heights.
How does the volume of a cone compare to that of a cylinder when they have the same radius $r$ and height $h$?
They are equal
The cone's volume is one-third of the cylinder's volume
The cone's volume is one-half of the cylinder's volume
The cone's volume is two-thirds of the cylinder's volume
Explanation
Using formulas: $V_{\text{cone}}=\tfrac{1}{3}\pi r^2 h$ and $V_{\text{cyl}}=\pi r^2 h$, so the cone is one-third of the cylinder. The common mistake is $\tfrac{1}{2}$, not $\tfrac{1}{3}$. Cavalieri's principle supports the $\tfrac{1}{3}$ factor for pyramids/cones.
A sphere of radius $r$ and a cylinder with radius $r$ and height $2r$ are compared. How does the sphere's volume compare to the cylinder's volume?
They are equal
The sphere's volume is half of the cylinder's volume
The sphere's volume is three-quarters of the cylinder's volume
The sphere's volume is two-thirds of the cylinder's volume
Explanation
Formulas: $V_{\text{sphere}}=\tfrac{4}{3}\pi r^3$ and $V_{\text{cyl}}=\pi r^2(2r)=2\pi r^3$, so $\tfrac{V_{\text{sphere}}}{V_{\text{cyl}}}=\tfrac{4/3}{2}=\tfrac{2}{3}$. By Cavalieri, at each height the cross-sectional area of the sphere equals that of the cylinder minus a cone, giving the same $\tfrac{2}{3}$ result; $\tfrac{1}{2}$ is a common distractor.
If the radius of a sphere doubles while nothing else changes, how does its volume change?
It is multiplied by 8
It is multiplied by 4
It is multiplied by 2
It is multiplied by 6
Explanation
For a sphere, $V=\tfrac{4}{3}\pi r^3$. Doubling $r$ multiplies volume by $2^3=8$. Confusing with surface area scaling leads to the incorrect factor of 4.
A cylinder and a cone have the same radius $r$ and height $2r$. How does $V_{\text{cylinder}}-V_{\text{cone}}$ compare to the volume of a sphere of radius $r$?
It is half the sphere's volume
It equals two-thirds of the sphere's volume
It equals the sphere's volume
It is larger than the sphere's volume
Explanation
$V_{\text{cyl}}=\pi r^2(2r)=2\pi r^3$ and $V_{\text{cone}}=\tfrac{1}{3}\pi r^2(2r)=\tfrac{2}{3}\pi r^3$. So $V_{\text{cyl}}-V_{\text{cone}}=\tfrac{4}{3}\pi r^3$, which equals $V_{\text{sphere}}$. By Cavalieri, the sphere and the cylinder-minus-cone have equal cross-sectional areas at each height, so their volumes are equal.
If both the radius and the height of a cylinder are tripled, how does its volume change?
It is multiplied by 9
It is multiplied by 27
It is multiplied by 6
It is multiplied by 3
Explanation
For a cylinder, $V=\pi r^2 h$. Tripling $r$ multiplies volume by $3^2=9$ and tripling $h$ multiplies it by $3$, for a total factor of $9\times3=27$. Choosing 9 or 3 misses one of the dimensions.