Whole Numbers - Basic Math

We can express Dr. Jones's rate in a linear equation:

Since Mrs. Smith's appointment lasted 30 minutes, we have 3 10-minute intervals. Then, we can plug in that number into our above equation to find out how much the appointment cost.

1. Round 145 to the nearest 10:

Since there is a 5 in the ones place, 145 rounds up to 150.

2. Divide the rounded number of baseballs by 10 since they come in packages of 10:

150/10=15 packages

Ones digit:

Tens digit: (leave the two at the tens, carry the one to the hundreds digit)

Hundreds digit: , add the one from the tens digit, so you get 5 + 1 = 6

Thousands digit:

First add the digits in the ones colume, this would be . Make sure to carry the 1 from the 17 to the tens colume.

Then add the digits in the tens colume, this would be .

Lastly, add the digits in the hundrends colume, this would be

Therefore the result is as follows:

1. Add the ones places:

2. Add the tens places:

***don't forget to put the 3 down and carry the one to the hundreds place***

3. Add the hundreds place:

This makes your total:

We can see this because if we had 5 (represented by ) and add another 2 objects (represented by ) we should get 7 objects ( and ) total.

We have 7 objects total!

If x represents objects.

For 5:

For 6:

We can see that 11 objects result.

When you subtract integers, it is the same thing as adding the inverse of the second integer. You can consider the following:

You can also consider the problem as asking for six less than negative four. This will also get you to the answer of .

The correct answer is 2 remaining toys. Kevin has 34 toys to start and he keeps 4 for himself. This means that he has 30 toys to give to four friends.

When we divide 30 by 4, we get 7.5. Since each friend cannot get half a toy, each friend can receive 7 toys.

This means that of the 30 toys, there will be 2 toys remaining.

Simply divide to answer this question:

remainder .

The maximum number of times can go into is , and you have left over.

To put it another way, . If you subtract from , you are left with , so that's your remainder.

We divide the top by the bottom.

Test how many times 10 fits into 32 (try 3 times).

We subtract 30 from 32:

10 cannot fit into 2 so the remainder is 2.

is not evenly divisible by . As such, you want to first find out how many whole 's can go into .

, so is too many.

, which is as close to as you can get.

, so that's your remainder.

So, we have blankets, and sleep over attendees.

can go into a maxiumum of times without going over, so each attendee gets blankets.

, , so there are blankets left over.

When you are dealing with negative numbers, the following rules apply.

If there are no negative signs, the answer is positive.

If there is one negative sign, the answer is negative.

If there are two negative signs, the answer is positive.

, and since there is only one negative sign the answer is negative. is the solution.

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Use a calculator to check your work if allowed, but if not, then I'd reccommend the following method, breaking the problem down into smaller pieces.

And then add your results:

We can see this by implementing objects.

groups of objects

^ We can see that there are 21 objects.

Start with . That gives . Write the ones' place down underneath the and the and carry the to the next place.

Next, do . That gives . However, remember to add the you carried over from the previous step.

Now, write down down next to the . Make sure the is lined up beneath the and and the is in the hundreds' place.

Now, do . Because we are multiplying using the tens' place of , you need to make sure that you write down the product of and in the tens' place, underneath the from your previous answer.

Next, do . Write this product () in the hundreds' place.

Finally, add these two numbers together.

To round to the nearest ten, you need to take a look at the ones' place. Since the ones' place is greater than , you will need to round the tens' place up.

So then is rounded up to .

You can simplify this problem:

, and , so if you simplify those parts of the equation, you are left with .

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