Buoyant Force - AP Physics 2

The net force on the ball is expressed as:

Since it is accelerating downward, we know that the force of gravity is stronger than the buoyant force, so we can write:

Substitute expressions for each variable:

Rearrange to solve for the volume of the ball:

To answer this question, we'll need to make use of the concept of buoyancy and apply the following equation:

Also, remember that in this equation, the density and volume are that of the fluid that is displaced, not that of the object!

Since we are told that the object has a mass of 300g and is initially floating, we can set the buoyant force equal to the weight of the object.

It's important to realize that the volume of the fluid displaced is going to be equal to that portion of the object's volume that is submerged underwater. Since we're told that the object is cylindrical, and that 4cm of its height is under water, we can set up the following relationship:

Where = Area of the cylinder and = height of cylinder underwater

Plugging this value into the above equation and canceling common units on both sides, we obtain:

Now that we have found the area, we can calculate the mass that needs to be added to the cylinder in order to make it sink. To do this, we need to consider the scenario in which the cyclinder is completely submerged in the water the instant before it is about to sink. In this case, we're able to calculate the mass that needs to be added to the cylinder to make this happen.

Where = the mass of mercury added to the cylinder

Thus far, we have determined that 450g of mercury needs to be added. Now, we just need to use the density of mercury in order to determine the volume needed.

Since the water is exerting an upward force on the metal sample, it is receiving a force of equal magnitude pointing downward by Newton's third law. This downward force is transmitted by increased pressure in the water to the beaker and then to the scale.

The minimum size of the ballon will exert a buoyant force exactly equal to the gravitational force:

Now we have to be careful. The mass is not just the mass of the man, but it includes the mass of the helium, as well. Canceling the 's and using subscripts to be careful:

The mass of the helium is its density times its volume:

Rearrange and solve for :

Buoyant forces can be thought of as the force caused by displacing the amount of water that was previously there. The buoyant force is the weight of the volume of the liquid displaced by the object. Since the two masses have the same diameter, they have the same volume and thus, the same buoyant force.

The buoyant force is the weight of the volume of water displaced by the immersed object. Since the rock is completely submerged, the buoyant force is the weight of water with the same volume as the rock. Despite the rock sinking, there is still a buoyant force; it is just less than the weight of the rock.

In this question, we're told that two identical objects are submerged in water. The only thing that differs between them is the distance under the surface of water at which they're submerged. We're then asked to determine how this affects the buoyant force that each one experiences.

To answer this, we'll need to remember the expression for buoyant force.

The above expression tells us that the magnitude of the buoyant force is proportional to the density of the water or fluid, the volume of the water displaced, and the acceleration due to gravity.

It's important to also realize that no where in this expression does it say that the buoyant force is related to the depth of the object. Therefore, because the two objects are the same, and because they're both fully submerged, they will both be displacing the same volume of water. Consequently, the buoyant force on each is the same.

The weight of the object is . If the scale reads , this tells us that the buoyancy force has a magnitude of . Mathematically:

We may relate these parameters by Archimedes' principle:

This allows us to solve for the volume of the sphere, and thus, the radius of the sphere.

Now we may use the formula for volume of a sphere to solve for the radius:

Use the equation for buoyant force:

Where is the density of the medium around the object in question

is the gravitational acceleration near the surface of the earth

is the volume of the object in question

Convert into

Plug in values:

Convert to and calculate volume:

Calculate buoyant force:

Plug in values:

Calculate force due to gravity:

Plug in values and solve:

Plug in values:

Consider all the forces on the gold marble:

Recall the equation for buoyant force:

Substitute:

Find the mass of the marble:

Plug in values:

Note how the buoyant force points up while the gravitational force points down.

In this question, we're presented with a situation in which two balls of different densities but equal volumes are held underneath the surface of a container of water. Then, each ball is released and allowed to accelerate up to the surface. The question is to determine how the acceleration of each ball compares to the other. In order to answer this, let's start by imagining all of the forces acting on the submerged ball.

In the x-direction, the forces acting to the left of the ball are exactly equal to the forces acting on the right of the ball. Therefore, all of the forces acting in the x-direction cancel out, resulting in a net force of zero in the x-direction.

In the y-direction, we have to consider two things. The first is the upward buoyant force caused by the displacement of water. Since both balls have an identical volume, both of them displace the same amount of water. Consequently, both balls will experience the same upward buoyant force. However, we must also consider the downward force caused by the weight of the ball itself. In this scenario, the downward weight of Ball B is greater than that of Ball A.

We can write the net force acting on the ball in the y-direction as the difference between the upward buoyant force and the downward weight as follows:

Due to the fact that Ball A has a smaller weight (a smaller component in the above equation), the result is that the net upward force is greater than that of Ball B. Thus, we would expect Ball A to have a greater acceleration.

Use the equation for buoyant force:

Where

is the density of the medium

is the acceleration due to gravity

is the volume

Plugging in values:

Determining density:

Volume of a sphere:

Combining equations:

Converting to and plugging in values:

It is denser than water, so it will sink.

Combining equations:

Plugging in values:

Solving for

According to Archimedes's principle, when the block is placed under water, 3.5L of water are displaced. We can then calculate the buoyant force provided by the water:

Where:

Plugging in our values to the first expression:

Then we can use Newton's 2nd law to determine the acceleration of the block:

There are two forces acting on the block, gravity and buoyancy, and they are in opposite directions. If we designate a downward force as positive, we get:

Substituting in the expression for force due to gravity:

Rearranging for acceleration:

Substituting in values:

We will start with Newton's 2nd law for this problem:

Where there are 4 total forces acting on the scuba diver and ball: gravity and buoyancy acting on both the scuba diver and the ball. However, the diver has the same density as the water, so the gravitational and buoyancy forces acting on the diver will cancel out. If we designate an upward force as being positive, we can say:

(1)

Where:

Where:

So,

Plugging these expressions back in to expression (1), we get:

Now let's start rearranging for the density of the ball:

The correct answer is that the buoyant force is equal to the weight of the water displaced by the object.

It is an upward force that is exerted on the object because of the volume of fluid displaced by that object.

The correct answer is

We know that the block is five times denser than the water. This means that a weight of the block would be the buoyant force which can be calculated as the following:

We can subtract the of weight from the original weight of the block which was

We obtain