Drawing Conclusions from Observations - AP Chemistry

The addition of so much salt (NaCl) caused the water to reach its solubility limit for NaCl. This means that no matter how much more NaCl you add to that solution or how hard you stir, it will not dissolve, and will precipitate on the bottom of the beaker. This type of solution is saturated. If the solution were unsaturated, then more salt would still be able to dissolve.

There is no special isotope that makes NaCl insoluble in water. The vigorous mixing would have separated any clumps, and if the solution was unsaturated the salt would have eventually dissolved. Magnesium chloride, another salt, is very soluble in water and would not result in the scenario described.

Each test gives us a different piece of information. The first test tells us that our compound is soluble in water. The second test tells us that heat is released when acid is added. The third test tells us that the solution turns red litmus paper blue, which means that the solution is basic. From these results, we can conclude that the compound is a water-soluble base. Now we can look at our answer options.

, , , and are all acids.

, however, will generate cyanide ions in solution. Cyanide is basic; thus, this is our correct answer.

The target is precise because the shots are closely grouped together. However, the shots are not accurate because they are not in the middle of the target.

The target is accurate because the shots are all in the middle of the target. It is also precise because all the shots are grouped together.

The shots are not precise because they are not grouped together. However, one of the shots is in the center of the target, and thus is accurate.

The addition of so much salt (NaCl) caused the water to reach its solubility limit for NaCl. This means that no matter how much more NaCl you add to that solution or how hard you stir, it will not dissolve, and will precipitate on the bottom of the beaker. This type of solution is saturated. If the solution were unsaturated, then more salt would still be able to dissolve.

There is no special isotope that makes NaCl insoluble in water. The vigorous mixing would have separated any clumps, and if the solution was unsaturated the salt would have eventually dissolved. Magnesium chloride, another salt, is very soluble in water and would not result in the scenario described.

Each test gives us a different piece of information. The first test tells us that our compound is soluble in water. The second test tells us that heat is released when acid is added. The third test tells us that the solution turns red litmus paper blue, which means that the solution is basic. From these results, we can conclude that the compound is a water-soluble base. Now we can look at our answer options.

, , , and are all acids.

, however, will generate cyanide ions in solution. Cyanide is basic; thus, this is our correct answer.

The target is precise because the shots are closely grouped together. However, the shots are not accurate because they are not in the middle of the target.

The target is accurate because the shots are all in the middle of the target. It is also precise because all the shots are grouped together.

The addition of so much salt (NaCl) caused the water to reach its solubility limit for NaCl. This means that no matter how much more NaCl you add to that solution or how hard you stir, it will not dissolve, and will precipitate on the bottom of the beaker. This type of solution is saturated. If the solution were unsaturated, then more salt would still be able to dissolve.

There is no special isotope that makes NaCl insoluble in water. The vigorous mixing would have separated any clumps, and if the solution was unsaturated the salt would have eventually dissolved. Magnesium chloride, another salt, is very soluble in water and would not result in the scenario described.

Each test gives us a different piece of information. The first test tells us that our compound is soluble in water. The second test tells us that heat is released when acid is added. The third test tells us that the solution turns red litmus paper blue, which means that the solution is basic. From these results, we can conclude that the compound is a water-soluble base. Now we can look at our answer options.

, , , and are all acids.

, however, will generate cyanide ions in solution. Cyanide is basic; thus, this is our correct answer.

The target is precise because the shots are closely grouped together. However, the shots are not accurate because they are not in the middle of the target.

The target is accurate because the shots are all in the middle of the target. It is also precise because all the shots are grouped together.

The shots are not precise because they are not grouped together. However, one of the shots is in the center of the target, and thus is accurate.

The addition of so much salt (NaCl) caused the water to reach its solubility limit for NaCl. This means that no matter how much more NaCl you add to that solution or how hard you stir, it will not dissolve, and will precipitate on the bottom of the beaker. This type of solution is saturated. If the solution were unsaturated, then more salt would still be able to dissolve.

There is no special isotope that makes NaCl insoluble in water. The vigorous mixing would have separated any clumps, and if the solution was unsaturated the salt would have eventually dissolved. Magnesium chloride, another salt, is very soluble in water and would not result in the scenario described.

Each test gives us a different piece of information. The first test tells us that our compound is soluble in water. The second test tells us that heat is released when acid is added. The third test tells us that the solution turns red litmus paper blue, which means that the solution is basic. From these results, we can conclude that the compound is a water-soluble base. Now we can look at our answer options.

, , , and are all acids.

, however, will generate cyanide ions in solution. Cyanide is basic; thus, this is our correct answer.

The target is precise because the shots are closely grouped together. However, the shots are not accurate because they are not in the middle of the target.

The target is accurate because the shots are all in the middle of the target. It is also precise because all the shots are grouped together.

The shots are not precise because they are not grouped together. However, one of the shots is in the center of the target, and thus is accurate.