Derivatives - AP Calculus AB
Card 1 of 7953
Find the derivative.

Find the derivative.
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The derivative of
is
. (Memorization)
The derivative of is
. (Memorization)
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Find
if the function
is given by

Find if the function
is given by
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To find the derivative at
, we first take the derivative of
. By the derivative rule for logarithms,

Plugging in
, we get

To find the derivative at , we first take the derivative of
. By the derivative rule for logarithms,
Plugging in , we get
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Find the derivative of the following function at the point
.

Find the derivative of the following function at the point .
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Use the power rule on each term of the polynomial to get the derivative,

Now we plug in 

Use the power rule on each term of the polynomial to get the derivative,
Now we plug in
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Let
. What is
?
Let . What is
?
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We need to find the first derivative of f(x). This will require us to apply both the Product and Chain Rules. When we apply the Product Rule, we obtain:
![f'(x)=\sin(x^2)\cdot\frac{\mathrm{d} }{\mathrm{d} x}[x^2]+x^2\cdot\frac{\mathrm{d} }{\mathrm{d} x}[\sin(x^2)]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/109754/gif.latex)
In order to find the derivative of
, we will need to employ the Chain Rule.
![\frac{\mathrm{d} }{\mathrm{d} x}[\sin(x^2)]=\cos(x^2)\cdot\frac{\mathrm{d} }{\mathrm{d} x}[x^2]=\cos(x^2)\cdot2x](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/128240/gif.latex)

We can factor out a 2x to make this a little nicer to look at.

Now we must evaluate the derivative when x =
.


The answer is
.
We need to find the first derivative of f(x). This will require us to apply both the Product and Chain Rules. When we apply the Product Rule, we obtain:
In order to find the derivative of , we will need to employ the Chain Rule.
We can factor out a 2x to make this a little nicer to look at.
Now we must evaluate the derivative when x = .
The answer is .
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Let
.
Find the second derivative of
.
Let .
Find the second derivative of .
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The second derivative is just the derivative of the first derivative. So first we find the first derivative of
. Remember the derivative of
is
, and the derivative for
is
.

Then to get the second derivative, we just derive this function again. So

The second derivative is just the derivative of the first derivative. So first we find the first derivative of . Remember the derivative of
is
, and the derivative for
is
.
Then to get the second derivative, we just derive this function again. So
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Define
.
What is
?
Define .
What is ?
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Take the derivative
of
, then take the derivative of
.





Take the derivative of
, then take the derivative of
.
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Define
.
What is
?
Define .
What is ?
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Take the derivative
of
, then take the derivative of
.





Take the derivative of
, then take the derivative of
.
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Define
.
What is
?
Define .
What is ?
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Rewrite:

&space;=&space;e%5E%7B-4x%7D)
Take the derivative
of
, then take the derivative of
.


Rewrite:
Take the derivative of
, then take the derivative of
.
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Define
.
What is
?
Define .
What is ?
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Take the derivative
of
, then take the derivative of
.

![g'(x) = 2x \cdot [-\sin (x^2)]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/136830/gif.latex)

![g''(x) = - 2\left [ 1 \cdot \sin(x^2)+ x \cdot 2x \cos(x^2) \right ]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/109772/gif.latex)
![g''(x) = - 2\left [ \sin(x^2)+ 2x^2 \cos(x^2) \right ]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/99997/gif.latex)
![g''(x) = - 2 \sin(x^2)-4x^2 \cos(x^2) \right ]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/136831/gif.latex)
Take the derivative of
, then take the derivative of
.
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Calculate the derivative:

Calculate the derivative:
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This is a chain rule using trigonometric functions.

Which upon simplifying is:

This is a chain rule using trigonometric functions.
Which upon simplifying is:
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What is the second derivative of
?
What is the second derivative of ?
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To get the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.


Remember that anything to the zero power is one.


Now we do the same process again, but using
as our expression:
)
Notice that
, as anything times zero will be zero.


Anything to the zero power is one.


To get the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
Remember that anything to the zero power is one.
Now we do the same process again, but using as our expression:
Notice that , as anything times zero will be zero.
Anything to the zero power is one.
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What is the second derivative of
?
What is the second derivative of ?
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To get the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
We're going to treat
as
, as anything to the zero power is one.
That means this problem will look like this:

Notice that
as anything times zero will be zero.


Remember, anything to the zero power is one.


Now to get the second derivative we repeat those steps, but instead of using
, we use
.

Notice that
as anything times zero will be zero.

To get the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
We're going to treat as
, as anything to the zero power is one.
That means this problem will look like this:
Notice that as anything times zero will be zero.
Remember, anything to the zero power is one.
Now to get the second derivative we repeat those steps, but instead of using , we use
.
Notice that as anything times zero will be zero.
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What is the second derivative of
?
What is the second derivative of ?
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To get the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
We're going to treat
as
, as anything to the zero power is one.

Notice that
, as anything times zero is zero.



Now we repeat the process using
as the expression.
Just like before, we're going to treat
as
.




To get the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
We're going to treat as
, as anything to the zero power is one.
Notice that , as anything times zero is zero.
Now we repeat the process using as the expression.
Just like before, we're going to treat as
.
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What is the concavity of
at x=1?
What is the concavity of at x=1?
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First, find the double derivative of the function given.
You should get
.
Next, plug in x=1 to get
.
The double derivative is a positive number, which means the concavity is Concave Up.
First, find the double derivative of the function given.
You should get .
Next, plug in x=1 to get .
The double derivative is a positive number, which means the concavity is Concave Up.
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Find the derivative of the function using the limit of the difference quotient:

Find the derivative of the function using the limit of the difference quotient:
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The derivative of a function,
, as defined by the limit of the difference quotient is

Taking the limit of our function - and remembering the limit at each step! - we get

The derivative of a function, , as defined by the limit of the difference quotient is
Taking the limit of our function - and remembering the limit at each step! - we get
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If
, what is
?
If , what is
?
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The question is asking us for the second derivative of the equation. First, we need to find the first derivative.
To do that, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat
as
since anything to the zero power is one.

Notice that
since anything times zero is zero.



Now we do the exact same process but using
as our expression.


As stated earlier, anything to the zero power is one.


The question is asking us for the second derivative of the equation. First, we need to find the first derivative.
To do that, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat as
since anything to the zero power is one.
Notice that since anything times zero is zero.
Now we do the exact same process but using as our expression.
As stated earlier, anything to the zero power is one.
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What is the second derivative of
?
What is the second derivative of ?
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To find the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat
as
since anything to the zero power is one.
)
Notice that
since anything times zero is zero.
That leaves us with
.
Simplify.


As stated earlier, anything to the zero power is one, leaving us with:

Now we can repeat the process using
or
as our equation.

As pointed out before, anything times zero is zero, meaning that
.
To find the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat as
since anything to the zero power is one.
Notice that since anything times zero is zero.
That leaves us with .
Simplify.
As stated earlier, anything to the zero power is one, leaving us with:
Now we can repeat the process using or
as our equation.
As pointed out before, anything times zero is zero, meaning that .
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What is the second derivative of
?
What is the second derivative of ?
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To find the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat
as
since anything to the zero power is one.

Notice that
since anything times zero is zero.



Just like it was mentioned earlier, anything to the zero power is one.


Now we repeat the process using
as our expression.

Like before, anything times zero is zero.


Anything to the zero power is one.


To find the second derivative, first we need to find the first derivative.
To do that, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat as
since anything to the zero power is one.
Notice that since anything times zero is zero.
Just like it was mentioned earlier, anything to the zero power is one.
Now we repeat the process using as our expression.
Like before, anything times zero is zero.
Anything to the zero power is one.
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When
, what is the concavity of the graph of
?
When , what is the concavity of the graph of
?
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To find the concavity, we need to look at the first and second derivatives at the given point.
To take the first derivative of this equation, use the power rule. The power rule says that we lower the exponent of each variable by one and multiply that number by the original exponent:

Simplify:

Remember that anything to the zero power is equal to one.


The first derivative tells us if the function is increasing or decreasing. Plug in the given point,
, to see if the result is positive (i.e. increasing) or negative (i.e. decreasing).


Therefore the function is increasing.
To find out if the function is convex, we need to look at the second derivative evaluated at the same point,
, and check if it is positive or negative.
We're going to treat
as
since anything to the zero power is equal to one.

Notice that
since anything times zero is zero.


Plug in our given value:


Since the second derivative is positive, the function is convex.
Therefore, we are looking at a graph that is both increasing and convex at our given point.
To find the concavity, we need to look at the first and second derivatives at the given point.
To take the first derivative of this equation, use the power rule. The power rule says that we lower the exponent of each variable by one and multiply that number by the original exponent:
Simplify:
Remember that anything to the zero power is equal to one.
The first derivative tells us if the function is increasing or decreasing. Plug in the given point, , to see if the result is positive (i.e. increasing) or negative (i.e. decreasing).
Therefore the function is increasing.
To find out if the function is convex, we need to look at the second derivative evaluated at the same point, , and check if it is positive or negative.
We're going to treat as
since anything to the zero power is equal to one.
Notice that since anything times zero is zero.
Plug in our given value:
Since the second derivative is positive, the function is convex.
Therefore, we are looking at a graph that is both increasing and convex at our given point.
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At the point
, is
increasing or decreasing, and is it concave or convex?
At the point , is
increasing or decreasing, and is it concave or convex?
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To find out if the function is increasing or decreasing, we need to look at the first derivative.
To find the first derivative, we can use the power rule. We lower the exponent on all the variables by one and multiply by the original variable.



Anything to the zero power is one.


Now we plug in our given value and find out if the result is positive or negative. If it is positive, the function is increasing. If it is negative, the function is decreasing.




Therefore, the function is decreasing.
To find out if it is concave or convex, look at the second derivative. If the result is positive, it is convex. If it is negative, then it is concave.
To find the second derivative, we repeat the process using
as our expression.
We're going to treat
as
.

Notice that
since anything times zero is zero.


As stated before, anything to the zero power is one.

Since we get a positive constant, it doesn't matter where we look on the graph, as our second derivative will always be positive. That means that this graph is going to be convex at our given point.
Therefore, the function is decreasing and convex at our given point.
To find out if the function is increasing or decreasing, we need to look at the first derivative.
To find the first derivative, we can use the power rule. We lower the exponent on all the variables by one and multiply by the original variable.
Anything to the zero power is one.
Now we plug in our given value and find out if the result is positive or negative. If it is positive, the function is increasing. If it is negative, the function is decreasing.
Therefore, the function is decreasing.
To find out if it is concave or convex, look at the second derivative. If the result is positive, it is convex. If it is negative, then it is concave.
To find the second derivative, we repeat the process using as our expression.
We're going to treat as
.
Notice that since anything times zero is zero.
As stated before, anything to the zero power is one.
Since we get a positive constant, it doesn't matter where we look on the graph, as our second derivative will always be positive. That means that this graph is going to be convex at our given point.
Therefore, the function is decreasing and convex at our given point.
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