Understanding Gametogenesis - AP Biology

Card 1 of 420

0
Didn't Know
Knew It
0
1 of 2019 left
Question

Which answer best explains why each primary spermatocyte cell (2n) results in the eventual production of four spermatids (n), while each oogonium cell (2n) results in the eventual production of only one active egg cell (n)?

Tap to reveal answer

Answer

Spermatogenesis is a continuous process starting at puberty. Sperm production takes place in the seminiferous tubules. There, each spermatogonium cell (2n) divides equally via mitosis to produce two identical primary spermatocytes (2n). Each primary spermatocyte undergoes meiosis I to produce two equally sized secondary spermatocytes (n). Each secondary spermatocyte then undergoes meiosis II to produce a total of four spermatids (n). The spermatids differentiate before moving to the epididymis.

Oogenesis, on the other hand, begins prior to birth and is a stop-start process. While still within the embryo, each oogonium (2n) produces two identical primary oocytes (2n) via mitosis; the primary oocytes remain dormant in small ovarian follicles until puberty. After the onset of puberty, hormones periodically stimulate the follicles to complete meiosis I and produce secondary oocytes (n). It is important to note, however, that meiosis I produces only one secondary oocyte—the other "daughter cell" is actually the first polar body, which is almost always rapidly degraded (though sometimes this polar body also undergoes meiosis II and produces a third polar body). This occurs because the primary oocyte divides unevenly, leaving the secondary oocyte with virtually all of the cytoplasm during cytokinesis. Secondary oocytes are released during ovulation, but they do not complete meiosis II until fertilization, when they are penetrated by a sperm. Meiosis II results in another polar body, again due to uneven division of cytoplasm during cytokinesis.

← Didn't Know|Knew It →