Simplifying Expressions - Algebra 2
Card 1 of 292
Simply: 
Simply:
Tap to reveal answer
In this form, the exponents are multiplied:
.
In multiplication problems, the exponents are added.
In division problems, the exponents are subtracted.
It is important to know the difference.
In this form, the exponents are multiplied: .
In multiplication problems, the exponents are added.
In division problems, the exponents are subtracted.
It is important to know the difference.
← Didn't Know|Knew It →
Simplify the expression.

Simplify the expression.
Tap to reveal answer
When multiplying exponential components, you must add the powers of each term together.


When multiplying exponential components, you must add the powers of each term together.
← Didn't Know|Knew It →
Expand:

Expand:
Tap to reveal answer
First, FOIL:

Simplify:

Distribute the
through the parentheses:

Rewrite to make the expression look like one of the answer choices:

First, FOIL:
Simplify:
Distribute the through the parentheses:
Rewrite to make the expression look like one of the answer choices:
← Didn't Know|Knew It →
Multiply, expressing the product in simplest form:

Multiply, expressing the product in simplest form:
Tap to reveal answer
Cross-cancel the coefficients by dividing both 15 and 25 by 5, and both 14 and 21 by 7:

Now use the quotient rule on the variables by subtracting exponents:

Cross-cancel the coefficients by dividing both 15 and 25 by 5, and both 14 and 21 by 7:
Now use the quotient rule on the variables by subtracting exponents:
← Didn't Know|Knew It →
Divide
by
.
Divide by
.
Tap to reveal answer
First, set up the division as the following:

Look at the leading term
in the divisor and
in the dividend. Divide
by
gives
; therefore, put
on the top:

Then take that
and multiply it by the divisor,
, to get
. Place that
under the division sign:

Subtract the dividend by that same
and place the result at the bottom. The new result is
, which is the new dividend.

Now,
is the new leading term of the dividend. Dividing
by
gives 5. Therefore, put 5 on top:

Multiply that 5 by the divisor and place the result,
, at the bottom:

Perform the usual subtraction:

Therefore the answer is
with a remainder of
, or
.
First, set up the division as the following:
Look at the leading term in the divisor and
in the dividend. Divide
by
gives
; therefore, put
on the top:
Then take that and multiply it by the divisor,
, to get
. Place that
under the division sign:
Subtract the dividend by that same and place the result at the bottom. The new result is
, which is the new dividend.
Now, is the new leading term of the dividend. Dividing
by
gives 5. Therefore, put 5 on top:
Multiply that 5 by the divisor and place the result, , at the bottom:
Perform the usual subtraction:
Therefore the answer is with a remainder of
, or
.
← Didn't Know|Knew It →
Simplify x(4 – x) – x(3 – x).
Simplify x(4 – x) – x(3 – x).
Tap to reveal answer
You must multiply out the first set of parenthesis (distribute) and you get 4x – x2. Then multiply out the second set and you get –3x + x2. Combine like terms and you get x.
x(4 – x) – x(3 – x)
4x – x2 – x(3 – x)
4x – x2 – (3x – x2)
4x – x2 – 3x + x2 = x
You must multiply out the first set of parenthesis (distribute) and you get 4x – x2. Then multiply out the second set and you get –3x + x2. Combine like terms and you get x.
x(4 – x) – x(3 – x)
4x – x2 – x(3 – x)
4x – x2 – (3x – x2)
4x – x2 – 3x + x2 = x
← Didn't Know|Knew It →
Expand: 
Expand:
Tap to reveal answer
To expand, multiply 8x by both terms in the expression (3x + 7).
8x multiplied by 3x is 24x².
8x multiplied by 7 is 56x.
Therefore, 8x(3x + 7) = 24x² + 56x.
To expand, multiply 8x by both terms in the expression (3x + 7).
8x multiplied by 3x is 24x².
8x multiplied by 7 is 56x.
Therefore, 8x(3x + 7) = 24x² + 56x.
← Didn't Know|Knew It →
Simplify the expression.

Simplify the expression.
Tap to reveal answer
When simplifying polynomials, only combine the variables with like terms.
can be added to
, giving
.
can be subtracted from
to give
.
Combine both of the terms into one expression to find the answer: 
When simplifying polynomials, only combine the variables with like terms.
can be added to
, giving
.
can be subtracted from
to give
.
Combine both of the terms into one expression to find the answer:
← Didn't Know|Knew It →
Simplify:

Simplify:
Tap to reveal answer
First, distribute –5 through the parentheses by multiplying both terms by –5.

Then, combine the like-termed variables (–5x and –3x).

First, distribute –5 through the parentheses by multiplying both terms by –5.
Then, combine the like-termed variables (–5x and –3x).
← Didn't Know|Knew It →
Find the product:

Find the product:
Tap to reveal answer
First, mulitply the mononomial by the first term of the polynomial:

Second, multiply the monomial by the second term of the polynomial:

Add the terms together:

First, mulitply the mononomial by the first term of the polynomial:
Second, multiply the monomial by the second term of the polynomial:
Add the terms together:
← Didn't Know|Knew It →
Evaluate the following to its simplest form:

Evaluate the following to its simplest form:
Tap to reveal answer

First we will foil the first function before distributing.


We will then distribute out the 

We will then distribute out the 

Now the only like terms we have are
and
, so our final answer is:

First we will foil the first function before distributing.
We will then distribute out the
We will then distribute out the
Now the only like terms we have are and
, so our final answer is:
← Didn't Know|Knew It →
Simplify:

Simplify:
Tap to reveal answer
. However,
cannot be simplified any further because the terms have different exponents.
(Like terms are terms that have the same variables with the same exponents. Only like terms can be combined together.)
. However,
cannot be simplified any further because the terms have different exponents.
(Like terms are terms that have the same variables with the same exponents. Only like terms can be combined together.)
← Didn't Know|Knew It →
Find the product: 
Find the product:
Tap to reveal answer
times
gives us
, while
times 4 gives us
. So it equals
.
times
gives us
, while
times 4 gives us
. So it equals
.
← Didn't Know|Knew It →
Simplify: 
Simplify:
Tap to reveal answer
and
cancel out, leaving
in the numerator. 5 and 25 cancel out, leaving 5 in the denominator
and
cancel out, leaving
in the numerator. 5 and 25 cancel out, leaving 5 in the denominator
← Didn't Know|Knew It →
Simplify the expression: 
Simplify the expression:
Tap to reveal answer
distributes to
, multiplying to become
, and
distributes to
, multiplying to make
.
distributes to
, multiplying to become
, and
distributes to
, multiplying to make
.
← Didn't Know|Knew It →
Distribute:

Distribute:
Tap to reveal answer
Be sure to distribute the
along with its coefficient.
Be sure to distribute the along with its coefficient.
← Didn't Know|Knew It →
Simplify the following:

Simplify the following:
Tap to reveal answer
In this problem, you have two fractions being multiplied. You can first simplify the coefficients in the numerators and denominators. You can divide and cancel the 2 and 14 each by 2, and the 3 and 15 each by 3:

You can multiply the two numerators and two denominators, keeping in mind that when multiplying like variables with exponents, you simplify by adding the exponents together:

Any variables that are both in the numerator and denominator can be simplified by subtracting the numerator's exponent by the denominator's exponent. If you end up with a negative exponent in the numerator, you can move the variable to the denominator to keep the exponent positive:

In this problem, you have two fractions being multiplied. You can first simplify the coefficients in the numerators and denominators. You can divide and cancel the 2 and 14 each by 2, and the 3 and 15 each by 3:
You can multiply the two numerators and two denominators, keeping in mind that when multiplying like variables with exponents, you simplify by adding the exponents together:
Any variables that are both in the numerator and denominator can be simplified by subtracting the numerator's exponent by the denominator's exponent. If you end up with a negative exponent in the numerator, you can move the variable to the denominator to keep the exponent positive:
← Didn't Know|Knew It →
Simplify the following:

Simplify the following:
Tap to reveal answer

First, FOIL the two binomials:

Then distribute the
through the terms in parentheses:

Combine like terms:

First, FOIL the two binomials:
Then distribute the through the terms in parentheses:
Combine like terms:
← Didn't Know|Knew It →
Simplify the following:

Simplify the following:
Tap to reveal answer

First we will factor the numerator:

Then factor the denominator:

We can re-write the original fraction with these factors and then cancel an (x-5) term from both parts:

First we will factor the numerator:
Then factor the denominator:
We can re-write the original fraction with these factors and then cancel an (x-5) term from both parts:
← Didn't Know|Knew It →
Simplify the following:

Simplify the following:
Tap to reveal answer

First, let us factor the numerator:


First, let us factor the numerator:
← Didn't Know|Knew It →