Elementary Operations - Algebra 2

To solve this system of equations by elimination you first need to multiply the first equation by -2. This will allow the y terms to cancel when equation 1 and equation 2 are adding together.

Now solve for x.

Substitute the x value into the orginial equation and solve for y.

To solve this system of equations by elimination you first need to multiply the first equation by -2. This will allow the y terms to cancel when equation 1 and equation 2 are adding together.

Now solve for x.

Substitute the x value into the orginial equation and solve for y.

To solve this system of equations by elimination you first need to multiply the first equation by -2. This will allow the y terms to cancel when equation 1 and equation 2 are adding together.

Now solve for x.

Substitute the x value into the orginial equation and solve for y.

Ignore the decimals first. Note that we will need to move the decimal of the final answer 4 places to the left.

We are multiplying .

Multiply the first number with the ones digit of the second number.

Multiply the first number with the tens digit of the second number.

Add a zero to the end of this number and add the first number.

Move the decimal place four places to the left.

The answer is:

Multiply the first number with the ones digit of the second number, 6.

Multiply the first number with the tens digit of the second number, 4.

Add a zero to the end of this number and add the first number.

The answer is:

In order to subtract the number, take the bigger number and subtract the smaller number, and then apply the negative sign.

The common factor of negative one can be pulled out to rearrange the numbers.

The coupon will entitle him to one free croissant, so Jerry will pay for the large espresso, the large cappucino, and one butter croissant. The charge will be the sum of the three prices:

Use the distance formula to solve this problem.

Plugging in our points A and B we get the following distance.

First, take the first equation and solve for x in terms of y.

From here, substitute the equation you found for x into the second equation and solve for y.

Now, substitute the y value found into the original equation and solve for x.

Simplify first by eliminating the parentheses. To do this you will need to distribute the coefficient term outside the parentheses to each term within the parentheses.

Next, combine like terms.

There is only one like-term in the expression given, which is .

Add the like term. The rest of the terms cannot be combined by adding or subtracting.

The correct answer is:

Add the ones digits.

Since this number is or greater, use the tens digit as a carry over.

Add the tens digits with the carry over.

Add the hundreds digit with the carry over. The hundreds digit for the second number in the problem is zero.

Since there is no carry over and there is no thousands digit for the second number, the thousands digit of the answer is just .

Combine all the ones digits in chronological order from thousands to the ones digits.

The answer is:

In order to simplify this, we need to combine like-terms. The coefficients of unlike terms cannot be combined.

Add and .

Add and .

Add and .

Combine all the terms.

The answer is:

In order to solve the problem, first evaluate .

Borrow a one from the six in the tens digit in order to subtract the ones digit.

The six in the tens digit becomes a five. Subtract the five with the tens digit of the second number.

Add .

Add the ones digit.

Since the number is ten or greater, use the tens digit as a carryover to the next calculation.

Combine the ones digits.

The answer is .

Combine the following terms:

To begin, we can consider each step independently. Because we are only dealing with addition and subtraction, the order we do this in does not matter. Rewrite as follows:

So there we go, is our answer.

Simplify the following expression:

Let's break this into parts.

First, realize that adding a negative number is the same as subtracting that number:

Next, subtract the 88:

Our answer must be negative, because 88 is bigger than 84. Therefore our answer is -4

When we add the functions together, we can only add terms that have matching exponents. First, let's add the terms that are squared:

Next, let's do the linear terms:

Finally, we add the constants:

Then we collect all the terms back together:

Add the ones digits.

The tens place is the carry over.

Add the tens digits with the carry over.

The tens place is the carry over for the next calculation.

Add the hundreds place with the carryover.

Combine this number with the ones digits of the previous calculations.

The answer is: