Basic Statistics - Algebra II
Card 0 of 1812
Determine the mean of the numbers: 
Determine the mean of the numbers:
The mean is the average of all the numbers in the data set.
Add all the numbers provided and divide the sum by a total of four, since there are four numbers given.
This fraction is irreducible.
The answer is: 
The mean is the average of all the numbers in the data set.
Add all the numbers provided and divide the sum by a total of four, since there are four numbers given.
This fraction is irreducible.
The answer is:
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Determine the mean: 
Determine the mean:
The mean is the average of all the numbers given in the set of data.
Add all the numbers.
Divide this number by the total numbers in the data set.
The answer is: 
The mean is the average of all the numbers given in the set of data.
Add all the numbers.
Divide this number by the total numbers in the data set.
The answer is:
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Identify the first and third quartiles for the following set of numbers.
{11, 14, 9, 2, 27, 26, 5, 8, 19, 10, 12, 6}
Identify the first and third quartiles for the following set of numbers.
{11, 14, 9, 2, 27, 26, 5, 8, 19, 10, 12, 6}
{11, 14, 9, 2, 27, 26, 5, 8, 19, 10, 12, 6}
First, arrange the values in numerical order.
{2, 5, 6, 8, 9, 10, 11, 12, 14, 19, 26, 27}
Quartiles are the values that divide a set into four equal parts. Since this set has twelve values, "cut" the data after the 3rd and 9th value to find the 1st and 3rd quartile, respectively.
{2, 5, 6,| 8, 9, 10, 11, 12, 14,| 19, 26, 27}
The quartile will be the average of the values on either side of the "cut."
First Quartile = (6+8)/2=7
Third Quartile = (14+19)/2=16.5
{11, 14, 9, 2, 27, 26, 5, 8, 19, 10, 12, 6}
First, arrange the values in numerical order.
{2, 5, 6, 8, 9, 10, 11, 12, 14, 19, 26, 27}
Quartiles are the values that divide a set into four equal parts. Since this set has twelve values, "cut" the data after the 3rd and 9th value to find the 1st and 3rd quartile, respectively.
{2, 5, 6,| 8, 9, 10, 11, 12, 14,| 19, 26, 27}
The quartile will be the average of the values on either side of the "cut."
First Quartile = (6+8)/2=7
Third Quartile = (14+19)/2=16.5
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Salespeople who land in the top quartile of average customer satisfaction ratings at the end of the year receive a bonus. Among the set of average ratings below, what is the cutoff for receiving the bonus?
{98, 55, 67, 88, 85, 91, 83, 65, 77, 83}
Salespeople who land in the top quartile of average customer satisfaction ratings at the end of the year receive a bonus. Among the set of average ratings below, what is the cutoff for receiving the bonus?
{98, 55, 67, 88, 85, 91, 83, 65, 77, 83}
{98, 55, 67, 88, 85, 91, 83, 65, 77, 83}
Rearrange the values in order.
{55, 65, 67, 77, 83, 83, 85, 88, 91, 98}
To get quartiles, "cut" the data into four.
{55, 65, 6**|7, 77, 83,|** 83, 85, 8**|**8, 91, 98}
As you can see, the third "cut" is right at 88. Which means 88 is the cutoff for the top quartile based on this set of data.
{98, 55, 67, 88, 85, 91, 83, 65, 77, 83}
Rearrange the values in order.
{55, 65, 67, 77, 83, 83, 85, 88, 91, 98}
To get quartiles, "cut" the data into four.
{55, 65, 6**|7, 77, 83,|** 83, 85, 8**|**8, 91, 98}
As you can see, the third "cut" is right at 88. Which means 88 is the cutoff for the top quartile based on this set of data.
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If Bob scores a 60, 80, and 90 on three of five tests in his class, what is the minimum average of Bob's fourth and fifth test scores in order for Bob to earn an overall score of 80 in his class?
If Bob scores a 60, 80, and 90 on three of five tests in his class, what is the minimum average of Bob's fourth and fifth test scores in order for Bob to earn an overall score of 80 in his class?
The test scores of Bob's fourth and fifth tests are unknown. Let Bob's fourth test score be 
and fifth test score be 
. Average all test scores.
Simplify the equation. Multiply by five on both sides.
Subtract 
from both sides.
The sum of Bob's fourth and fifth test must add up to this value.
To average the test scores, simply divide both sides by two. This will be the minimum average of both test four and five.
The answer is: 
The test scores of Bob's fourth and fifth tests are unknown. Let Bob's fourth test score be
Simplify the equation. Multiply by five on both sides.
Subtract
The sum of Bob's fourth and fifth test must add up to this value.
To average the test scores, simply divide both sides by two. This will be the minimum average of both test four and five.
The answer is:
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Determine the mean of the following numbers: 
Determine the mean of the following numbers:
In order to determine the mean of the numbers, sum the numbers and divide the sum by the total amount of numbers provided in the data set.
Divide this number by five since there are five numbers.
The mean is: 
In order to determine the mean of the numbers, sum the numbers and divide the sum by the total amount of numbers provided in the data set.
Divide this number by five since there are five numbers.
The mean is:
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Determine the mean of the numbers: 
Determine the mean of the numbers:
To determine the average of the numbers in the data set, we will need to add all the numbers in the data set and divide the sum by the total numbers in the data set.
Simplify this fraction by adding the numerator.
The answer is: 
To determine the average of the numbers in the data set, we will need to add all the numbers in the data set and divide the sum by the total numbers in the data set.
Simplify this fraction by adding the numerator.
The answer is:
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Determine the mean of the following data set: 
Determine the mean of the following data set:
The mean is the average of all the numbers provided in the data set.
Add all the numbers.
Divide this value by four since there are four numbers given.
The mean is: 
The mean is the average of all the numbers provided in the data set.
Add all the numbers.
Divide this value by four since there are four numbers given.
The mean is:
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Find the median of the set:
Find the median of the set:
The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an even amount of numbers in the set meaning there are two "middle numbers"- 23 and 25. In order to find the median we take the average of 23 and 25:
The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an even amount of numbers in the set meaning there are two "middle numbers"- 23 and 25. In order to find the median we take the average of 23 and 25:
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Draw a Box and Whisker plot for the following data set.
Draw a Box and Whisker plot for the following data set.
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile: 
, 
, 
Median of 1st quartile: 
2nd quartile = Median of total set: 
3rd quartile: 
, 
, 
Median of 3rd quartile: 
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
The endpoints (black dots) represent the smallest and largest values, in this case, 2 and 39.
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile:
Median of 1st quartile:
2nd quartile = Median of total set:
3rd quartile:
Median of 3rd quartile:
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
The endpoints (black dots) represent the smallest and largest values, in this case, 2 and 39.
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Draw a Box and Whisker plot for the following data set.
Draw a Box and Whisker plot for the following data set.
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile: 
Median of 1st quartile: 
2nd quartile = Median: 
3rd quartile:
Median of 3rd quartile: 
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile:
Median of 1st quartile:
2nd quartile = Median:
3rd quartile:
Median of 3rd quartile:
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
Compare your answer with the correct one above
Draw a box and whisker plot for the following data set.
Draw a box and whisker plot for the following data set.
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile: 
Median of 1st quartile: 
2nd quartile = Median: 
3rd quartile: 
Median of 3rd quartile: 
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile:
Median of 1st quartile:
2nd quartile = Median:
3rd quartile:
Median of 3rd quartile:
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
Compare your answer with the correct one above
Draw a Box and Whisker plot for the following data set.
Draw a Box and Whisker plot for the following data set.
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile: 
Median of 1st quartile: 
2nd quartile= Median: 
3rd quartile: 
Median of 3rd quartile: 
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines.
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile:
Median of 1st quartile:
2nd quartile= Median:
3rd quartile:
Median of 3rd quartile:
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines.
Compare your answer with the correct one above
Draw a Box and Whisker plot for the following data set.
Draw a Box and Whisker plot for the following data set.
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile: 
Median of 1st quartile: 
2nd quartile = Median: 
3rd quartile: 
Median of 3rd quartile: 
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile:
Median of 1st quartile:
2nd quartile = Median:
3rd quartile:
Median of 3rd quartile:
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
Compare your answer with the correct one above
Draw a Box and Whisker plot for the following data set.
Draw a Box and Whisker plot for the following data set.
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile: 
Median of 1st quartile: 
2nd quartile = Median: 
3rd quartile: 
Median of 3rd quartile: 
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves.
1st quartile:
Median of 1st quartile:
2nd quartile = Median:
3rd quartile:
Median of 3rd quartile:
To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows:
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The box and whisker plot above can be used to find all of the following information about the data set that it describes except:
The box and whisker plot above can be used to find all of the following information about the data set that it describes except:
The median value of the data set, 86, is represented by the dashed line inside the box.
The maximum and minimum of the data set, 100 and 75 (respectively), are found at the far ends of the 2 whiskers on either end.
The range of the data set is found by subtracting the minimum from the maximum; 100-75=25, so the range is 25.
The upper and lower quartiles are given by the two boundaries between the box and the whiskers: the lower quartile (1st quartile) is the left boundary, 80 in the data set; the upper quartile (3rd quartile) is the right boundary, which is 92 in the data set.
All of the other choices are provided by the box and whisker plot, so the correct choice is "The box and whisker plot gives you all of these"
The median value of the data set, 86, is represented by the dashed line inside the box.
The maximum and minimum of the data set, 100 and 75 (respectively), are found at the far ends of the 2 whiskers on either end.
The range of the data set is found by subtracting the minimum from the maximum; 100-75=25, so the range is 25.
The upper and lower quartiles are given by the two boundaries between the box and the whiskers: the lower quartile (1st quartile) is the left boundary, 80 in the data set; the upper quartile (3rd quartile) is the right boundary, which is 92 in the data set.
All of the other choices are provided by the box and whisker plot, so the correct choice is "The box and whisker plot gives you all of these"
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Refer to the above graph. Carla, a sixth grader at Polk, outscored 101 of the students who took the test. Which of these could her score have been?
Refer to the above graph. Carla, a sixth grader at Polk, outscored 101 of the students who took the test. Which of these could her score have been?
students achieved scores between 200 and 600, and Carla outscored all of them.
students achieved scores between 200 and 700. However, Carla did not outscore all of them.
Carla's score had to have been between 600 and 700, so of the five choices, 660 is the only possible one.
Carla's score had to have been between 600 and 700, so of the five choices, 660 is the only possible one.
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Above is a stem-and-leaf representation of the scores on a test administered to a group of students. What was the midrange of the scores?
Above is a stem-and-leaf representation of the scores on a test administered to a group of students. What was the midrange of the scores?
The midrange is the mean of the highest and lowest scores.
Each "stem" in the left column represents the tens digits of the scores; each of the numbers in its row, or "leaf" represents the units digits. The lowest score is represented by the 4 "leaf" in the "3" row - that is, it is 34 - and the highest score is represented by the 8 "leaf" in the "9" row - that is, 98. The midrange is therefore
The midrange is the mean of the highest and lowest scores.
Each "stem" in the left column represents the tens digits of the scores; each of the numbers in its row, or "leaf" represents the units digits. The lowest score is represented by the 4 "leaf" in the "3" row - that is, it is 34 - and the highest score is represented by the 8 "leaf" in the "9" row - that is, 98. The midrange is therefore
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Refer to the above bar graph.
How many students at Polk Middle School scored above 550 on the math portion of the SCAT?
Refer to the above bar graph.
How many students at Polk Middle School scored above 550 on the math portion of the SCAT?
The dividing points of the intervals used to classify students on this graph occur at multiples of 100. No details are given for each interval beyond the number of students who scored in it, so, for example, within the interval 500-600, it is not made clear how many of the 40 students scored above or below 550. The answer is that insufficient information is provided.
The dividing points of the intervals used to classify students on this graph occur at multiples of 100. No details are given for each interval beyond the number of students who scored in it, so, for example, within the interval 500-600, it is not made clear how many of the 40 students scored above or below 550. The answer is that insufficient information is provided.
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The following histogram shows the highest level of education attained by the employees of a local store.
How many employees are working for the store?
The following histogram shows the highest level of education attained by the employees of a local store.
How many employees are working for the store?
Solution
The height of each bar shows the number of employees who attained that particular level of education. So to find the total number of employees, we add the numbers shown by all the bars in the histogram.
The total number of employees is 200.
Solution
The height of each bar shows the number of employees who attained that particular level of education. So to find the total number of employees, we add the numbers shown by all the bars in the histogram.
The total number of employees is 200.
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