How to find the equation of a line

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ACT Math › How to find the equation of a line

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1

Let y = 3_x_ – 6.

At what point does the line above intersect the following:

They do not intersect

0

They intersect at all points

CORRECT

(0,–1)

0

(–5,6)

0

(–3,–3)

0

Explanation

If we rearrange the second equation it is the same as the first equation. They are the same line.

2

Which of the following is the equation of a line between the points and ?

CORRECT

0

0

0

0

Explanation

Since you have y-intercept, this is very easy. You merely need to find the slope. Then you can use the form to find one version of the line.

The slope is:

Thus, for the points and , it is:

Thus, one form of our line is:

If you move the to the left side, you get:

, which is one of your options.

3

What line goes through the points (1, 3) and (3, 6)?

3x + 5y = 2

0

2x – 3y = 5

0

4x – 5y = 4

0

–3x + 2y = 3

CORRECT

–2x + 2y = 3

0

Explanation

If P1(1, 3) and P2(3, 6), then calculate the slope by m = rise/run = (y2 – y1)/(x2 – x1) = 3/2

Use the slope and one point to calculate the intercept using y = mx + b

Then convert the slope-intercept form into standard form.

4

What is the slope-intercept form of \dpi{100} \small 8x-2y-12=0?

\dpi{100} \small y=4x-6

CORRECT

\dpi{100} \small y=4x+6

0

\dpi{100} \small y=2x-3

0

\dpi{100} \small y=-4x+6

0

\dpi{100} \small y=-2x+3

0

Explanation

The slope intercept form states that \dpi{100} \small y=mx+b. In order to convert the equation to the slope intercept form, isolate \dpi{100} \small y on the left side:

\dpi{100} \small 8x-2y=12

\dpi{100} \small -2y=-8x+12

\dpi{100} \small y=4x-6

5

Which of the following equations does NOT represent a line?

CORRECT

0

0

0

0

Explanation

The answer is .

A line can only be represented in the form or , for appropriate constants , , and . A graph must have an equation that can be put into one of these forms to be a line.

represents a parabola, not a line. Lines will never contain an term.

6

Given the graph of the line below, find the equation of the line.

Act_math_160_04

0

0

CORRECT

0

Explanation

To solve this question, you could use two points such as (1.2,0) and (0,-4) to calculate the slope which is 10/3 and then read the y-intercept off the graph, which is -4.

7

What is an equation of the line going through points and ?

CORRECT

0

0

0

0

Explanation

If you have two points, you can always use the point-slope form of a line to find your equation. Recall that this is:

You first need to find the slope, though. Recall that this is:

For the points and , it is:

Thus, you can write the equation using either point:

Now, notice that one of the options is:

This is merely a multiple of the equation we found, so it is fine!

8

A line is defined by the following equation:

What is the slope of that line?

CORRECT

0

0

0

0

Explanation

The equation of a line is

y=mx + b where m is the slope

Rearrange the equation to match this:

7x + 28y = 84

28y = -7x + 84

y = -(7/28)x + 84/28

y = -(1/4)x + 3

m = -1/4

9

Which line passes through the points (0, 6) and (4, 0)?

y = 2/3x –6

0

y = –3/2x + 6

CORRECT

y = 1/5x + 3

0

y = 2/3 + 5

0

y = –3/2 – 3

0

Explanation

P1 (0, 6) and P2 (4, 0)

First, calculate the slope: m = rise ÷ run = (y2 – y1)/(x2 – x1), so m = –3/2

Second, plug the slope and one point into the slope-intercept formula:

y = mx + b, so 0 = –3/2(4) + b and b = 6

Thus, y = –3/2x + 6

10

If the coordinates (3, 14) and (_–_5, 15) are on the same line, what is the equation of the line?

CORRECT

0

0

0

0

Explanation

First solve for the slope of the line, m using y=mx+b

m = (y2 – y1) / (x2 – x1)

= (15 14) / (_–_5 _–_3)

= (1 )/( _–_8)

=_–_1/8

y = (1/8)x + b

Now, choose one of the coordinates and solve for b:

14 = (1/8)3 + b

14 = _–_3/8 + b

b = 14 + (3/8)

b = 14.375

y = (1/8)x + 14.375